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python – 一元的坏操作数类型:’str’

作者:互联网

我无法弄清楚我在使用Python 2.7编写的代码时遇到的问题.我正在将引用转换为int,但我一直得到一个类型异常坏操作数类型为一元:’str’.有人可以帮忙吗?

import urllib2
import time
import datetime

stocksToPull = 'EBAY', 'AAPL'


def pullData(stock):
    try:
        print 'Currently pulling', stock
        print str(datetime.datetime.fromtimestamp(time.time()).strftime('%Y-%m-%d %H:%M:%S'))
        urlToVisit = 'http://chartapi.finance.yahoo.com/instrument/1.0/' + \
            stock + '/chartdata;type=quote;range=3y/csv'
        saveFileLine = stock + '.txt'

        try:
            readExistingData = open(saveFileLine, 'r').read()
            splitExisting = readExistingData.split('\n')
            mostRecentLine = splitExisting[-2]
            lastUnix = mostRecentLine.split(',')[0]
        except Exception, e:
            print str(e)
            time.sleep(1)
            lastUnix = 0

        saveFile = open(saveFileLine, 'a')
        sourceCode = urllib2.urlopen(urlToVisit).read()
        splitSource = sourceCode.split('\n')

        for eachLine in splitSource:
            if 'values' not in eachLine:
                splitLine = eachLine.split(',')
                if len(splitLine) == 6:
                    if int(splitLine[0]) > int(lastUnix):
                        lineToWrite = eachLine + '\n'
                        saveFile.write(lineToWrite)
        saveFile.close()

        print 'Pulled', + stock
        print 'Sleeping....'
        print str(datetime.datetime.fromtimestamp(time.time()).strftime('%Y-%m-%d %H:%M:%S'))
        time.sleep(120)

    except Exception, e:
        print 'main loop', str(e)


for eachStock in stocksToPull:
    pullData(eachStock)

我打算一元的操作数异常坏操作数类型:’str’当它到达if int(splitLine [0])> int(lastUnix):即使被比较的两个值在测试时打印为整数.任何人都可以给我一些反馈吗?谢谢!

这是异常响应:

Currently pulling EBAY
2013-12-21 11:32:40
Pulled main loop bad operand type for unary +: 'str'
Currently pulling AAPL
2013-12-21 11:32:41
Pulled main loop bad operand type for unary +: 'str'`

解决方法:

你说如果int(splitLine [0])> int(lastUnix):引起了麻烦,但实际上并没有显示任何暗示的东西.
我认为这一行是问题所在:

print 'Pulled', + stock

你明白为什么这一行会导致错误信息?你也想要

>>> stock = "AAAA"
>>> print 'Pulled', stock
Pulled AAAA

要么

>>> print 'Pulled ' + stock
Pulled AAAA

>>> print 'Pulled', + stock
PulledTraceback (most recent call last):
  File "<ipython-input-5-7c26bb268609>", line 1, in <module>
    print 'Pulled', + stock
TypeError: bad operand type for unary +: 'str'

你要求Python将符号应用于像23这样的字符串使得积极的23,并且她反对.

标签:python,operands
来源: https://codeday.me/bug/20191005/1856908.html