Python:继续检查新电子邮件并提醒更多新电子邮件
作者:互联网
我有这个代码检查最新的电子邮件,然后去做一些事情.是否有可能写一些不断检查收件箱文件夹的新邮件?虽然我希望它继续检查最新的新电子邮件.如果我尝试存储它已经通过一次会变得太复杂吗?因此,它不会就同一封电子邮件两次发送同一封邮件.
码:
import imaplib
import email
import Tkinter as tk
word = ["href=", "href", "<a href="] #list of strings to search for in email body
#connection to the email server
mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login('xxxx', 'xxxx')
mail.list()
# Out: list of "folders" aka labels in gmail.
mail.select("Inbox", readonly=True) # connect to inbox.
result, data = mail.uid('search', None, "ALL") # search and return uids instead
ids = data[0] # data is a list.
id_list = ids.split() # ids is a space separated string
latest_email_uid = data[0].split()[-1]
result, data = mail.uid('fetch', latest_email_uid, '(RFC822)') # fetch the email headers and body (RFC822) for the given ID
raw_email = data[0][1] # here's the body, which is raw headers and html and body of the whole email
# including headers and alternate payloads
.....goes and does other code regarding to email html....
解决方法:
尝试使用这种方法:
逻辑与@tripleee评论相同.
import time
word = ["href=", "href", "<a href="] #list of strings to search for in email body
#connection to the email server
mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login('xxxx', 'xxxx')
mail.list()
# Out: list of "folders" aka labels in gmail.
latest_email_uid = ''
while True:
mail.select("Inbox", readonly=True)
result, data = mail.uid('search', None, "ALL") # search and return uids instead
ids = data[0] # data is a list.
id_list = ids.split() # ids is a space separated string
if data[0].split()[-1] == latest_email_uid:
time.sleep(120) # put your value here, be sure that this value is sufficient ( see @tripleee comment below)
else:
result, data = mail.uid('fetch', latest_email_uid, '(RFC822)') # fetch the email headers and body (RFC822) for the given ID
raw_email = data[0][1]
latest_email_uid == data[0].split()[-1]
time.sleep(120) # put your value here, be sure that this value is sufficient ( see @tripleee comment below)
标签:python,email,imaplib 来源: https://codeday.me/bug/20191003/1849315.html