python – 确定Shapely点是否在LineString / MultiLineString中

我试图在函数内使用Shapely来进行LineString和Point文件的“空间连接”(FYI,点文件是使用LineString上的插值函数生成的).问题是 – 什么都没有归还.

# this condition is never satisfied
if point.within(line):
    # here I write stuff to a file

哪里：

point = POINT (-9763788.9782693591000000 5488878.3678984242000000)
line = LINESTRING (-9765787.998118492 5488940.974948905, -9748582.801636808 5488402.127570709)

我错过了什么？

解决方法:

在线上找到点时存在浮点精度误差.请使用具有适当阈值的距离.

from shapely.geometry import Point, LineString

line = LineString([(-9765787.9981184918, 5488940.9749489054), (-9748582.8016368076, 5488402.1275707092)])
point = Point(-9763788.9782693591, 5488878.3678984242)

line.within(point)  # False
line.distance(point)  # 7.765244949417793e-11
line.distance(point) < 1e-8  # True

标签：point,shapely,python
来源： https://codeday.me/bug/20191002/1840759.html