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python学习笔记,视频day14-集合,字符串格式化

作者:互联网

分类:

可变不可变

  可变:列表,字典

  不可变:字符串,数字,元组

访问顺序

  直接访问:数字

  顺序访问:列表,字符串,元组

  映射:字典

存放元素个数

  容器类型:列表,元组,字典

  原子:数字,字符串

集合:

  1.不同元素组成

  2.无序

  3.元素必须是不可变类型(可哈希的值)

  交集   intersection    &

  并集   union     |

  差集   difference    -

  交叉补集   symmetric_difference

方法:

#集合
s=set("hello")
print(s)
s=set(["alex","hello"])
print(s)
# 结果
# {'l', 'h', 'e', 'o'}
# {'hello', 'alex'}
# 添加add
s={1,2,3,4,5,6}
s.add(22)
s.add(2)
s.add('3')
print(s)
# 结果
# {1, 2, 3, 4, 5, 6, '3', 22}
s={1,2,3,4,5,6}
s.clear()
print(s)
# 结果
# set()
# 删除,随机
s={1,2,3,4,5,6}
s.pop()
print(s)
# 结果
# {2, 3, 4, 5, 6}
# 指定删除,不存在时会报错
s={1,2,3,4,5,6}
s.remove(2)
print(s)
# 结果
# {1, 3, 4, 5, 6}
# 指定删除,不存在时不会报错
s={1,2,3,4,5,6}
s.discard('22')
print(s)
# 结果
# {1, 2, 3, 4, 5, 6}
# 更新s1,更新多个值
s1={1,2}
s2={3,5,43,1}
print(s1.update(s2),s1,s2)
# print(s1.union(s2),s1,s2)#不更新
# 结果
#None {1, 2, 3, 5, 43} {43, 3, 5, 1}
# 集合可以用来判断关系
python_1=["yangzi","siqi","chenglong","yunqianyue"]
linux_1=["yangzi","daqiao","chenglong"]
p_s=set(python_1)
l_s=set(linux_1)
print(p_s,l_s)
# 交集
print(p_s.intersection(l_s))
print(p_s&l_s)
# 结果
# {'chenglong', 'yangzi'}
# 并集
print(p_s.union(l_s))
print(p_s|l_s)
# 结果
# {'yunqianyue', 'yangzi', 'siqi', 'daqiao', 'chenglong'}
# 差集
print(p_s.difference(l_s))
print(p_s-l_s)
# 结果
# {'yunqianyue', 'siqi'}

# 交叉补集
print(p_s.symmetric_difference(l_s))
# 结果
# {'yunqianyue', 'daqiao', 'siqi'}
python_1=["yangzi","siqi","chenglong","yunqianyue"]
linux_1=["yangzi","daqiao","chenglong"]
p_s=set(python_1)
l_s=set(linux_1)
print(p_s,l_s)
# v=l_s.intersection_update(p_s)
l_s.intersection_update(p_s)
print(p_s,l_s)
# 结果
# None {'yunqianyue', 'yangzi', 'siqi', 'chenglong'} {'yangzi', 'chenglong'}
# 是否有交集,否返回True
s1={1,2}
s2={3,5,43}
print(s1.isdisjoint(s2))
# 结果
# True
# s1是s2的子集,返回True
s1={1,2}
s2={3,5,43,1,2}
print(s1.issubset(s2))
# 结果
# True

补充:

  集合是可变的,可通过frozenset定义不可变集合

s=frozenset("hello")
print(s)
# 简单去重
names=["yangzi","siqi","chenglong","yunqianyue","siqi"]
s=list(set(names))
print(s)
#结果
#['yunqianyue', 'chenglong', 'yangzi', 'siqi']

 

字符串格式化

常规

  %拼接,键方式

format用法

 

  %s    字符串,接受所有

  %d    数字,只能接受数字

  %f    小数

补充:

  sep拼接

# 字符串格式化
msg="i am "+"yang"
print(msg)
# 结果
# i am yang
msg="i am %s hobby is %s"%('yang','swimming')
print(msg)
# 结果
# i am yang hobby is swimming
msg="i am %s hobby is %d"%('yang',22)
print(msg)
# 结果
# i am yang hobby is 22
#打印浮点数
msg="i am %s hobby is %f"%('yang',22.2222223335678)
print(msg)
# # 结果
# # i am yang hobby is 22.222222
# 打印%
msg="i am %s hobby is %2f%%"%('yang',22.2222223335678)
print(msg)
# 结果
# i am yang hobby is 22.222222%
# 键方式
tp1="i am %(name)s hobby is %(bo)s"%{"name":"yang","bo":"Swim"}
print(tp1)
# 结果
# i am yang hobby is Swim
# 右对齐,颜色\033
tp1="i am \033[43:1m%(name)-20s hobby\033[0m is %(bo)s"%{"name":"yang","bo":"Swim"}
print(tp1)
# 结果
# i am yang hobby is Swim
# 拼接符
print("root","a","z",sep="-")
# 结果
# root-a-z

format用法

 

# format
# 一一对应
tp1="i am {},age {},hobby {}".format("yang",18,"swim")
print(tp1)
# 结果
# i am yang,age 18,hobby swim
tp1="i am {2},age {0},hobby {1}".format("yang",18,"swim")
print(tp1)
# 结果
# i am swim,age yang,hobby 18
tp1="i am {name},age {a},hobby {h}".format(name="yang",a=15,h="swim")
print(tp1)
# 结果
# i am yang,age 15,hobby swim
tp1="i am {:s},age {:s},hobby {:s}".format(*["a","b","s",2],[222,"g"])
print(tp1)
# 结果
# i am a,age b,hobby s
tp1="i am {name},age {a},hobby {h}".format(**{"name":"yang","a":1,"h":"swim"})
print(tp1)
# 结果
# i am yang,age 1,hobby swim

# :b 二进制,:o八进制
tp1="{:b},{:o},{:d},{:x},{:X},{:%}".format(15,15,15,15,15,15.3334,33,"dd")
print(tp1)
# 结果
# 1111,17,15,f,F,1533.340000%

(视频8未看)

标签:格式化,结果,python,am,day14,yang,tp1,print,hobby
来源: https://www.cnblogs.com/ppll/p/11524866.html