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python:概括委托方法

作者:互联网

我有一个这样的类包含一个或多个数字元素.

class Foo:
    # ... other methods ...
    def _update(self, f):
        # ... returns a new Foo() object based on transforming
        #     one or more data members with a function f()
    def __add__(self, k):
        return self._update(lambda x: x.__add__(k))
    def __radd__(self, k):
        return self._update(lambda x: x.__radd__(k))
    def __sub__(self, k):
        return self._update(lambda x: x.__sub__(k))
    def __rsub__(self, k):
        return self._update(lambda x: x.__rsub__(k))
    def __mul__(self, k):
        return self._update(lambda x: x.__mul__(k))
    def __rmul__(self, k):
        return self._update(lambda x: x.__rmul__(k))
    def __div__(self, k):
        return self._update(lambda x: x.__div__(k))
    def __rdiv__(self, k):
        return self._update(lambda x: x.__rdiv__(k))
    # I want to add other numeric methods also

是否有任何方法可以为所有numeric methods推广这一点,而不必为每一个都做到这一点?

我只想委托数值方法列表中的任何方法.

解决方法:

您希望在此使用operator module以及二进制数字运算符名称的(简短)列表,而不使用下划线来表示紧凑性:

import operator 

numeric_ops = 'add div floordiv mod mul pow sub truediv'.split()

def delegated_arithmetic(handler):
    def add_op_method(op, cls):
        op_func = getattr(operator, op)
        def delegated_op(self, k):
            getattr(self, handler)(lambda x: op_func(x, k))
        setattr(cls, '__{}__'.format(op), delegated_op)

    def add_reflected_op_method(op, cls):
        op_func = getattr(operator, op)
        def delegated_op(self, k):
            getattr(self, handler)(lambda x: op_func(k, x))
        setattr(cls, '__r{}__'.format(op), delegated_op)

    def decorator(cls):
        for op in numeric_ops:
            add_op_method(op, cls)
            add_reflected_op_method(op, cls) # reverted operation
            add_op_method('i' + op, cls)     # in-place operation
        return cls

    return decorator

现在只需装饰你的班级:

@delegated_arithmetic('_update')
class Foo:
    # ... other methods ...
    def _update(self, f):
        # ... returns a new Foo() object based on transforming
        #     one or more data members with a function f()

装饰器使用您想要委派调用的名称来使其更通用.

演示:

>>> @delegated_arithmetic('_update')
... class Foo(object):
...     def _update(self, f):
...         print 'Update called with {}'.format(f)
...         print f(10)
... 
>>> foo = Foo()
>>> foo + 10
Update called with <function <lambda> at 0x107086410>
20
>>> foo - 10
Update called with <function <lambda> at 0x107086410>
0
>>> 10 + foo
Update called with <function <lambda> at 0x107086410>
20
>>> 10 - foo
Update called with <function <lambda> at 0x107086410>
0

标签:python,magic-methods
来源: https://codeday.me/bug/20190831/1779130.html