javascript – 使多个回调与jQuery $.when同步

这是我的示例代码：

function out(msg)
{
  $('#output').append(msg + '<br>');
}

var myDeferred = [];
$.each([8, 3, 4, 6, 9, 15, 7, 1], function (index, time)
{
  myDeferred.push($.Deferred(function(dfd)
  {
    setTimeout(function ()
    {
      out(time);
      dfd.resolve();
    }, time * 1000);
  }).promise());
});

$.when.apply($, myDeferred).then(function ()
{
  out('all is done');
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="output"></div>

此输出“1 3 4 6 7 8 9 15全部完成”,同时调用所有回调.

但我希望“8 3 4 6 9 15 7 1全部完成”,所有回调都是一个接一个地调用.

有人可以帮帮我吗？

提前致谢

解决方法:

问题是每个回调超时几乎同时被激活.您可以执行以下操作：

function out(msg)
{
  $('#output').append(msg + '<br>');
}

function foo(index, callback) {
  var time = array[index];
  out(time);
  if (index == array.length - 1)
    callback();
  else
    setTimeout(foo, time * 1000, index + 1, callback);
}

var array = [8, 3, 4, 6, 9, 15, 7, 1];
foo(0, function ()
{
  out('all is done');
});

使用承诺：

function out(msg)
{
  $('#output').append(msg + '<br>');
}

var myDeferred = [];
$.each([8, 3, 4, 6, 9, 15, 7, 1], function (index, time)
{
  myDeferred.push($.Deferred(function(dfd)
  {
    var f = function() {
      out(time);
      dfd.resolve();
    }
    if (index > 0)
      myDeferred[index - 1].done(function() { setTimeout(f, time * 1000); });
    else 
      setTimeout(f, time * 1000);
  }).promise());
});

$.when.apply($, myDeferred).then(function ()
{
  out('all is done');
});

标签：javascript,jquery,asynchronous,synchronization,jquery-deferred
来源： https://codeday.me/bug/20190830/1765720.html