php – 有没有更有效的方法来创建年/月的列表？

在页面上,我想动态列出每年的年份和所有月份,以便查看每个月的存档.我想先显示当前年份,但今年可能还没有结束,所以我只想显示已经过去的月份和当月.然后我想要从今年开始的所有年份和所有月份(即2008年).

我创建的PHP代码完成了以下工作.有没有更有效的方法来实现这一目标？我正在运行PHP 5.2.

$current_year = date('Y');
$months = array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12);

// Loop through all the months and create an array up to and including the current month
foreach ($months as $month)
{
    if ($month <= date('m'))
    {
        switch ($month)
        {
            case 1:
                $years[$current_year][] = 'January';
                break;
            case 2:
                $years[$current_year][] = 'February';
                break;
            case 3:
                $years[$current_year][] = 'March';
                break;
            case 4:
                $years[$current_year][] = 'April';
                break;
            case 5:
                $years[$current_year][] = 'May';
                break;
            case 6:
                $years[$current_year][] = 'June';
                break;
            case 7:
                $years[$current_year][] = 'July';
                break;
            case 8:
                $years[$current_year][] = 'August';
                break;
            case 9:
                $years[$current_year][] = 'September';
                break;
            case 10:
                $years[$current_year][] = 'October';
                break;
            case 11:
                $years[$current_year][] = 'November';
                break;
            case 12:
                $years[$current_year][] = 'December';
                break;
        }
    }
}

// Previous years
$years_to_create = $current_year - 2008;

if (!empty($years_to_create))
{
    for ($i = 1; $i <= $years_to_create; $i++)
    {
        $years[$current_year - $i] = array('January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December');
    }
} 

解决方法:

$current_year = date('Y');
$months = array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12);
$month_names = array('January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December');

// Loop through all the months and create an array up to and including the current month

for ($month=1;$month<=date('m');$month++)
{
$years[$current_year][] = $month_names[$month-1];
}

// Previous years
$years_to_create = $current_year - 2008;

if (!empty($years_to_create))
{
    for ($i = 1; $i <= $years_to_create; $i++)
    {
        $years[$current_year - $i] = $month_names;
    }
}

这似乎有点简单……是否更快……？

标签：php,performance,datetime,language-agnostic
来源： https://codeday.me/bug/20190827/1744151.html