php – 在抽象类中测试私有方法扩展了另一个
作者:互联网
我正在尝试在抽象类中测试私有方法.
我有三个抽象类:
abstract class AbstractClass1 extends AbstractClass2
{
private function _privateFunction()
{
//method's body
}
}
abstract class AbstractClass2 extends AbstractClass3
{
public function __construct($param)
{
parent::__construct($param)
}
}
abstract class AbstractClass3
{
public function __construct($param = array())
{
//something
}
}
测试类:
class AbstractClass1Test extends PHPUnit_Framework_TestCase
{
public function test_privateFunction()
{
$stub = $this->getMockForAbstractClass("AbstractClass1");
$class = new ReflectionClass($stub);
$method = $class->getMethod("_privateFunction");
$method->setAccessible(true);
//some assertings with $method->invoke($stub)
}
}
测试失败,因为错误:
Missing argument 1 for AbstractClass2::__construct(), called in /usr/share/php/PHPUnit/Framework/MockObject/Generator.php on line 190 and defined
AbstractClass2.php
public function __construct($param)
AbstractClass1.php
$classMock = $this->getMockForAbstractClass("AbstractClass1");
Generator.php:190
if ($callOriginalConstructor &&
!interface_exists($originalClassName, $callAutoload)) {
if (count($arguments) == 0) {
<strong>$mockObject = new $mock['mockClassName'];</strong>
} else {
$mockClass = new ReflectionClass($mock['mockClassName']);
$mockObject = $mockClass->newInstanceArgs($arguments);
}
} else ...
我错了什么?或者我如何在这种情况下测试我的私人功能?
解决方法:
您需要将参数传递给AbstractClass1的构造函数.将数组中的构造函数参数作为getMockForAbstractClass()的第二个参数传递.
$stub = $this->getMockForAbstractClass("AbstractClass1", array('param'));
标签:extending,php,unit-testing,abstract-class,phpunit 来源: https://codeday.me/bug/20190826/1733026.html