java – System.out.print同时打印两行/题.我究竟做错了什么？

所以我正在为类分配工作,在我完成并修复了编译器发现的所有错误后,我在运行程序时得到了这个：

  J:\Java Class>java AddressDemo

   What is your Street's name?     Unknown RD

   What is your zip code?  1234565

   What is your State?
   What is your house number?

它同时询问这两个问题并等待输入.

这是我的代码：

import java.util.Scanner;

public class AddressDemo
{
    public static void main(String[] args)
    {
        Address address = new Address();
        Scanner input = new Scanner(System.in);

        String Street;
        int Zip;
        String State;
        String City;
        int house;

        // Get the student's input

        System.out.println();
        System.out.print("What is your Street's name?\t");
        Street = input.nextLine();

        System.out.println();
        System.out.print("What is your zip code?\t");
        Zip = input.nextInt();

        System.out.println();
        System.out.print("What is your State?\t");
        State = input.nextLine();

        System.out.println();
        System.out.print("What is your house number?\t");
        house = input.nextInt();

        System.out.println();
        System.out.print(" What is your city?\t");
        City = input.nextLine();


        // Processing
        address.setStName(Street);
        address.setZNum(Zip);
        address.setSName(State);
        address.setCName(City);
        address.setHNum(house);


        //Output isn't finished
        System.out.println("\nYour address is:" + address.getHNum() + address.getStName() + address.getCName() +address.getSName()
                                        + address.getZNum() + " !");
        }
}

这是我需要的其他文件的代码：

public class Address
{
    private int HNum;
    private String StName;
    private String CName;
    private String SName;
    private int ZNum;
    private String LNum;

    public boolean setHNum (int hn)
    {
        HNum = hn;
        return true;
    }

    public String getHNum()
    {
        return String.format("%08d", HNum);
    }

    public boolean setStName(String str)
    {
        StName = str;
        return true;
    }

    public String getStName()
    {
        return StName;
    }

    public boolean setCName(String City)
    {
        CName = City;
        return true;
    }

    public String getCName()
    {
        return CName;
    }

    public boolean setSName(String st)
    {
        SName = st;
        return true;
    }

    public String getSName()
    {
        return SName;
    }

    public boolean setZNum ( int zip)
    {
        ZNum = zip;
        return true;
    }

    public String getZNum()
    {
        return String.format("%08d", ZNum);
    }

    public boolean setLNum (String l2)
    {
        LNum = l2;
        return true;
    }

    public String getLNum()
    {
        return String.format("%08d", LNum);
    }

}

解决方法:

使用input.nextInt()时,它不会使用结束输入的换行符.结果是当您提示下一个输入(状态)时,它会立即读取剩余的换行符,将空字符串分配给State,并提示输入门牌号.您应该使用input.nextLine()来读取邮政编码(以及稍后的门牌号)并将该行解析为int.或者,在调用nextInt()之后调用nextLine()并忽略返回值.

我想建议邮政编码应该只是一个字符串,以便你保留前导零并可以处理zip 4地址.同样,门牌号码应该是一个字符串来处理像贝克街221b这样的地址.当然,这将需要更改您的Address类定义以及更改读取输入的方式.

标签：java-util-scanner,java,system-out
来源： https://codeday.me/bug/20190824/1713251.html