使用Javascript将对象(元素)向上移动一步

我有几个像这样的对象：

我想将类型和值向上移动一步,以便它们将在字段旁边,然后删除数据.
部门转换为JSON时看起来像这样：

[
    {"field"    : "DEPARTMAN_NO",
     "data"     : { "type":"numeric" , "comparison":"eq" , "value":11 }
    },
    {"field"    : "DEPARTMAN_ADI",
     "data"     : { "type":"string" , "value":"bir" }
    }
]

我试过了：

departments = grid.filters.getFilterData();
i = {};
for(var i in department) {
department = i.data;
delete.department.data;
};

但它不起作用.

解决方法:

1)首先,循环部门,我们称之为部门的每个项目;
2)您想将department.data的属性移动到department,从另一个角度来看,您可以将department的属性移动到department.data并返回department.data,代码如下：

var departments = [{
        "field": "DEPARTMAN_NO",
        "data": {
            "type": "numeric",
            "comparison": "eq",
            "value": 11
        }
    }, {
        "field": "DEPARTMAN_ADI",
        "data": {
            "type": "string",
            "value": "bir"
        }
    }],
    department;

for (var i = 0, len = departments.length; i < len; i++) {
    department = departments[i]; // department
    for (var key in department) {
        if (key !== 'data' && department.data) {
            department.data[key] = department[key];
        }
    }
    departments[i] = department.data || department; // if no department.data, no change
}

console.log(departments);

结果：

查看完整的演示http://jsfiddle.net/KVYE5/

标签：extjs4-1,javascript,javascript-objects,object,filter
来源： https://codeday.me/bug/20190823/1696271.html