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首页 > 编程语言> > Disarium Number(特殊号码系列#3)【难度:1级】--景越Python编程训练之挑战1000道Python面试题(含答案)

Disarium Number(特殊号码系列#3)【难度:1级】--景越Python编程训练之挑战1000道Python面试题(含答案)

作者:互联网

Disarium Number(特殊号码系列#3)【难度:1级】:

#Definition

** _ Disarium number _ **是用其各自位置驱动的数字总和等于数字本身的数字。


#任务

** 一个数字, _查找它是否是Disarium _ **。


#热身(强烈推荐)

#[玩数字系列](https://www.codewars.com/collections/playing-with-numbers)


#Notes


#Input >>输出示例

1- disariumNumber(89)==>返回“Disarium !!”

** 解释 **:

因为,* _ 8 1 </ sup> + 9 2 </ sup> = 89 _ **,因此输出是“Disarium !!”


2- disariumNumber(564)==>返回“不!!”

** 解释 **:

因为,** _ 5 1 </ sup> + 6 2 </ sup> + 4 3 </ sup> = 105!= 546 _ **,因此输出是“不! !“`




#[玩数字系列](https://www.codewars.com/collections/playing-with-numbers)

#[使用列表/数组矩阵系列](https://www.codewars.com/collections/playing-with-lists-slash-arrays)

#[更加愉快的Katas](http://www.codewars.com/users/MrZizoScream/authored)


##欢迎所有翻译

##享受学习!!
#Zizou

英文原题:

Definition

Disarium number is the number that The sum of its digits powered with their respective positions is equal to the number itself.


Task

Given a number, Find if it is Disarium or not .


Warm-up (Highly recommended)

Playing With Numbers Series


Notes


Input >> Output Examples

1- disariumNumber(89) ==> return "Disarium !!"

Explanation:


2- disariumNumber(564) ==> return "Not !!"

Explanation:

Since , 51 + 62 + 43 = 105 != 546 , thus output is "Not !!"




Playing with Numbers Series

Playing With Lists/Arrays Series

For More Enjoyable Katas


ALL translations are welcomed

Enjoy Learning !!

Zizou

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标签:面试题,景越,Python,number,89,www,sup,Disarium
来源: https://blog.csdn.net/aumtopsale/article/details/98090299