python – 像文档一样解析sphinx
作者:互联网
我有一个sphinx格式的docstring,我想从中提取不同的部分(param,return,type,rtype等)以便进一步处理.我怎样才能做到这一点?
解决方法:
你可以使用docutils,这是Sphinx的基础.在this other answer中,我使用docutils.core.publish_doctree来获取reStructuredText文档的XML表示(实际上是一串文本),然后使用xml.minidom方法从该XML中提取字段列表.另一种方法是使用xml.etree.ElementTree,这在我看来更容易使用.
然而,首先,每次docutils遇到一个reStructuredText块时
:param x: Some parameter
得到的XML表示(我知道,它非常详细):
<field_list>
<field>
<field_name>
param x
</field_name>
<field_body>
<paragraph>
Some parameter
</paragraph>
</field_body>
</field>
</field_list>
以下代码将获取文档中的所有field_list元素,并将field / field_name和field / field_body / paragraph中的文本作为2元组放入列表中.然后,您可以按照您希望的方式操作后期处理.
from docutils.core import publish_doctree
import xml.etree.ElementTree as etree
source = """Some help text
:param x: some parameter
:type x: and it's type
:return: Some text
:rtype: Return type
Some trailing text. I have no idea if the above is valid Sphinx
documentation!
"""
doctree = publish_doctree(source).asdom()
# Convert to etree.ElementTree since this is easier to work with than
# xml.minidom
doctree = etree.fromstring(doctree.toxml())
# Get all field lists in the document.
field_lists = doctree.findall('field_list')
fields = [f for field_list in field_lists \
for f in field_list.findall('field')]
field_names = [name.text for field in fields \
for name in field.findall('field_name')]
field_text = [etree.tostring(element) for field in fields \
for element in field.findall('field_body')]
print zip(field_names, field_text)
这产生了列表:
[('param x', '<field_body><paragraph>some parameter</paragraph></field_body>'),
('type x', "<field_body><paragraph>and it's type</paragraph></field_body>"),
('return', '<field_body><paragraph>Some text</paragraph></field_body>'),
('rtype', '<field_body><paragraph>Return type</paragraph></field_body>')]
因此,每个元组中的第一项是字段列表项(即:return:,:param x:etc),第二项是相应的文本.显然这个文本并不是最干净的输出 – 但上面的代码很容易修改,所以我把它留给OP来获得他们想要的确切输出.
标签:python,parsing,documentation,python-sphinx,docstring 来源: https://codeday.me/bug/20190723/1512491.html