Python for-in-loop停止对从for-in-loop 创建的列表对象的迭代

参见英文答案 > Removing from a list while iterating over it                                    4个
[有史以来第一个Stack-o-flow Python初学者用户的问题]

我一直在尝试创建一个附加数字1到10然后在python列表对象中从10擦除到1的函数.
然而,我成功了,我遇到了for-in循环的奇怪行为.

以下是我的所作所为&成功：

def a():
    li = []

    for i in range(1,11):
        li.append(i)
        print(li)

    for n in range(1,11):
        li.remove(li[-1])
        print(li)

a()

会打印：

[1]
[1, 2]
[1, 2, 3]
[1, 2, 3, 4]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5, 6]
[1, 2, 3, 4, 5, 6, 7]
[1, 2, 3, 4, 5, 6, 7, 8]
[1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4, 5, 6, 7, 8]
[1, 2, 3, 4, 5, 6, 7]
[1, 2, 3, 4, 5, 6]
[1, 2, 3, 4, 5]
[1, 2, 3, 4]
[1, 2, 3]
[1, 2]
[1]
[]

但是,如果我将其for循环范围(1,11)的第二部分更改为li,则迭代将停止,如下所示.

def a():
    li = []

    for i in range(1,11):
        li.append(i)
        print(li)

    for n in li:         <-------------- THIS PART
        li.remove(li[-1])
        print(li)

a()

会打印：

[1]
[1, 2]
[1, 2, 3]
[1, 2, 3, 4]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5, 6]
[1, 2, 3, 4, 5, 6, 7]
[1, 2, 3, 4, 5, 6, 7, 8]
[1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4, 5, 6, 7, 8]
[1, 2, 3, 4, 5, 6, 7]
[1, 2, 3, 4, 5, 6]
[1, 2, 3, 4, 5]

所以,我查了一下对象li的长度.

def a():
    li = []
    for i in range(1,11):
        li.append(i)
        print(li)

    print("Length before passed: ", len(li))

    for n in li: <------------ THIS
        print("Length BEFORE REMOVE: ", len(li))

        li.remove(li[-1])

        print("Length AFTER REMOVE: ", len(li))
        print(li)
a()

会打印：

[1]
[1, 2]
[1, 2, 3]
[1, 2, 3, 4]
[1, 2, 3, 4, 5]
[1, 2, 3, 4, 5, 6]
[1, 2, 3, 4, 5, 6, 7]
[1, 2, 3, 4, 5, 6, 7, 8]
[1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
Length before passed:  10
Length BEFORE REMOVE:  10
Length AFTER REMOVE:  9
[1, 2, 3, 4, 5, 6, 7, 8, 9]
Length BEFORE REMOVE:  9
Length AFTER REMOVE:  8
[1, 2, 3, 4, 5, 6, 7, 8]
Length BEFORE REMOVE:  8
Length AFTER REMOVE:  7
[1, 2, 3, 4, 5, 6, 7]
Length BEFORE REMOVE:  7
Length AFTER REMOVE:  6
[1, 2, 3, 4, 5, 6]
Length BEFORE REMOVE:  6
Length AFTER REMOVE:  5
[1, 2, 3, 4, 5] <---- And it stops here.

这里发生了什么？
为什么python for-loop会在完整循环之前停止？

非常感谢你.

解决方法:

在您的情况下,迭代会因为您从头开始迭代而停止,但您同时从末尾删除元素：

>第1次迭代以9个元素结束,因此循环进入第2个元素.
>第二次迭代以8个元素结束,因此循环前进到第3个元素
> ……
>第5次迭代以5个元素结束,没有第6个元素继续进行,循环结束.

这就是为什么在迭代它时改变列表通常是不可取的.

标签：python,iteration,python-3-x,for-in-loop
来源： https://codeday.me/bug/20190722/1499903.html