java – 使用SearchView的Android abs,onQueryTextListener无效
作者:互联网
我正在尝试使用带有操作栏sherlock的SearchView支持v4版本.
所以我在操作栏中有我的搜索按钮 – >当我触摸它时键盘显示和搜索栏也.
我的问题是我需要使用侦听器onQueryTextSubmit和onQueryTextChange但它们永远不会被触发.我需要使用searh查询字符串并使用它做自定义的东西.
这是完整的activity.java
public class ActivityMain extends SherlockFragmentActivity implements OnQueryTextListener, DialogFragmentListener {
/**
* PRIVATE ATTRIBUTES
*/
private static final String TAG = "ActivityMain";
private ViewPager _viewPager;
private TabsAdapter _tabsAdapter;
private DialogFiltre _dialogFiltre;
private String _searchCurrentQuery;
// data
private boolean _doubleBackToExitPressedOnce = false;
@Override
public boolean onPrepareOptionsMenu(Menu menu) {
menu.clear();
switch ((int) _viewPager.getCurrentItem()) {
case 0:
getSupportMenuInflater().inflate(R.menu.empty_menu, menu);
break;
case 1:
getSupportMenuInflater().inflate(R.menu.action_bar_menu, menu);
break;
case 2:
getSupportMenuInflater().inflate(R.menu.empty_menu, menu);
break;
}
return super.onPrepareOptionsMenu(menu);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getSupportMenuInflater().inflate(R.menu.action_bar_menu, menu);
MenuItem searchItem = menu.findItem(R.id.search);
SearchView searchView = (SearchView) searchItem.getActionView();
searchView.setSubmitButtonEnabled(true);
searchView.setOnQueryTextListener(queryTextListener);
return true;
}
@Override
public boolean onQueryTextSubmit(String query) {
Log.i(TAG, "onQueryTextSubmit--");
onSearchClicked(query);
// hide keyboard
InputMethodManager inputManager = (InputMethodManager) this.getSystemService(Context.INPUT_METHOD_SERVICE);
inputManager.hideSoftInputFromWindow(this.getCurrentFocus().getWindowToken(), InputMethodManager.HIDE_NOT_ALWAYS);
return false;
}
@Override
public boolean onQueryTextChange(String newText) {
Log.d(TAG, "onQueryTextChange--");
_searchCurrentQuery = newText.toString();
EtablissementApplication._adapter.getFilter().filter(_searchCurrentQuery);
return true;
}
private void onSearchClicked(String query) {
Log.d(TAG, "onSearchClicked--");
_searchCurrentQuery = query.toString();
EtablissementApplication._adapter.getFilter().filter(_searchCurrentQuery);
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
switch (item.getItemId()) {
case android.R.id.home:
getSupportActionBar().setDisplayHomeAsUpEnabled(false);
break;
case R.id.search:
break;
case R.id.menu_filtre:
_dialogFiltre = DialogFiltre.newInstance(R.string.menu_filtre, this);
_dialogFiltre.setValidDialogListener(this);
_dialogFiltre.show(getSupportFragmentManager(), null);
break;
}
return super.onOptionsItemSelected(item);
}
解决方法:
您正在尝试使用新的SearchView,而不是使用SupportMenuInflater创建的SearchView.
您将侦听器设置为您在屏幕上看到的不同SearchView.
此外,每次调用onPrepareOptionsMenu时,都会创建新的SearchView,因此它没有设置侦听器.
尝试像这样做onPrepareOptionsMenu:
@Override
public boolean onPrepareOptionsMenu(Menu menu) {
menu.clear();
switch ((int) _viewPager.getCurrentItem()) {
case 0:
getSupportMenuInflater().inflate(R.menu.empty_menu, menu);
break;
case 1:
getSupportMenuInflater().inflate(R.menu.action_bar_menu, menu);
MenuItem searchItem = menu.findItem(R.id.search);
SearchView searchView = (SearchView) searchItem.getActionView();
searchView.setSubmitButtonEnabled(true);
searchView.setOnQueryTextListener(queryTextListener);
break;
case 2:
getSupportMenuInflater().inflate(R.menu.empty_menu, menu);
break;
}
return super.onPrepareOptionsMenu(menu);
}
并删除重写的方法
@Override
public boolean onCreateOptionsMenu(Menu menu) { }
标签:java,android,actionbarsherlock,searchview,searchable 来源: https://codeday.me/bug/20190718/1493024.html