javascript – 角度事件成功提交表单时打开弹出窗口
作者:互联网
我有一个页面,通过angular $http.post(..)将数据发布到ASPNET MVC页面
当电话结束时我必须提交一份表格.
基本上我做以下事情:
<html ng-app>
<body data-ng-controller="testController">
<form id="Checkpay" name="Checkpay" style="margin: 0" method="post" action="https://www.sandbox.paypal.com/cgi-bin/webscr" target="_blank" class="ng-pristine ng-valid">
<input type="hidden" name="quantita" id="qtytext" value="0">
<input type="hidden" name="cmd" value="_xclick">
<input type="hidden" name="item_name" value="Le Spose di Nika">
<input type="hidden" name="business" value="TEST@TEST.it">
<input type="hidden" name="currency_code" value="EUR">
<input type="hidden" name="cancel_return" id="cancel_return" value="">
<input type="hidden" name="return" id="return" value="">
<input type="hidden" name="no_shipping" value="1">
<input type="hidden" id="H_amount" name="amount" value="719.80">
<input type="hidden" id="H_first_name" name="first_name">
<input type="hidden" id="H_address1" name="address1">
<input type="hidden" id="H_city" name="city">
<input type="hidden" id="H_state" name="state">
<input type="hidden" id="H_zip" name="zip">
<input type="hidden" id="H_email" name="email">
<input type="hidden" id="Country" name="country">
<input type="hidden" id="charset" name="charset" value="utf8">
<input type="hidden" id="rm" name="rm" value="2">
<input type="hidden" id="notify_url" name="notify_url" value="">
<input id="Submit1" type="submit" value="submit_post" />
</form>
<input id="Submit2" type="button" data-ng-click='pay()' value="js_post" />
</body>
</html>
<script src="http://localhost:27433/Scripts/jquery-1.7.1.min.js"></script>
<script src="http://localhost:27433/Scripts/jquery-ui-1.8.20.min.js"></script>
<script src="http://localhost:27433/Scripts/angular.js"></script>
<script>
function test() {
}
function testController($scope, $http) {
var URL = "http://backend.MYSITE.com/";
$scope.payTest = function () {
var PAYPAL_URL_RELEASE = "https://www.paypal.com/cgi-bin/webscr";
var PAYPAL_URL_SANDBOX = "https://www.sandbox.paypal.com/cgi-bin/webscr";
$('#cancel_return').val(URL + '/ErrorPay');
$('#return').val(URL + '/Success');
$('#notify_url').val(URL + '/PayPalReceiverIPN.ashx?idOrder=');
document.forms["Checkpay"].action = PAYPAL_URL_RELEASE;
document.forms["Checkpay"].submit();
console.log('paytest is executed!');
}
$scope.pay = function () {
////$.post( URL + "/Order/Create", JSON.stringify({ newOrder: 1 }))
//// .success(function (datdata, status, headers, configa) {
//// console.log(' $.post success');
//// $scope.payTest();
//// }).error(function (data, status, headers, config) {
//// console.log(' $.post failure');
//// });
$http.post(
URL + "/Order/Create", JSON.stringify({ newOrder: 1 })
).success(function (datdata, status, headers, configa) {
console.log('http success');
$scope.payTest();
}).error(function (data, status, headers, config) {
console.log('http failure');
});
}
}
</script>
当我做document.forms [“Checkpay”].submit();我方面有一个重定向
到我的表单的属性操作的页面,而不是我将重定向页面的弹出窗口.
我试图将函数payTest()从“成功”中取出然后它起作用然后我认为问题是
对象$http(或ajax)如何处理“success”委托.
问题是:当$http.post(….)完成调用时,无论如何都要对页面进行重定向?
谢谢
解决方法:
您的payTest功能是否完全执行?
我会这样做:
function testController($scope, $http) {
$scope.pay = function () {
$http({
method: 'POST',
url: 'http://backend.mysite.com/Order/Create',
data: JSON.stringify({ $scope.newOrder: 1 })
})
['success'](function (data, status, headers, config) {
console.log('http success');
$scope.payTest();
})
['error'](function (data, status, headers, config) {
console.log('http failure');
});
};
$scope.payTest = function() {
console.log('paytest is executed!');
// all your stuff
};
}
更新:我将$http调用的语法更改为我一直使用的语法.
标签:jquery,javascript,angularjs,form-submit,popupwindow 来源: https://codeday.me/bug/20190708/1405865.html