python – 在OpenERP 7.0的列表视图中按选择排序

在OpenERP 7列表视图中,我想显示订单草稿中的状态值排序,当前在Asc或Desc中显示已分配和取消.但在我的情况下,我们需要在订单草稿,分配和取消状态中进行排序.基于在python文件中的顺序应用

例如在SQL代码中 –

select state, date from  object_name
ORDER BY CASE WHEN state = 'draft'  THEN 0 
              WHEN state = 'assigned'  THEN 1 
              WHEN state = 'cancel'  THEN 2
              ELSE 3
END,  date desc

上面的sql代码在python中应用

_order = ("CASE WHEN state='draft'  THEN 0",
          "WHEN state = 'assigned'  THEN 1",
          "ELSE 2 END, date desc")

在上面的查询排序选择值工作在pg_admin但在python代码中它显示错误

Invalid "order" specified. A valid "order" specification is a comma-separated
list of valid field names (optionally followed by asc/desc for the direction)

基于此排序顺序的选择值如何在OpenERP中应用？覆盖搜索方法也应用了相同的sql查询但显示相同的问题.

解决方法:

尝试使用store属性创建一个功能字段,该属性在状态更改时加载函数.
例如

def _get_state(cr, uid, ids,field_name, context=None):
    res={}
    for obj in self.browse(cr, uid, ids, context):
        res[obj.id] = (obj.state=='draft' and 0) or (obj.state=='assigned' and 1) or (obj.state=='cancel' and 2) or 3
    return res

_columns = {
current_state_num: fields.function(_get_state,string='Current state',type='integer',store={'your.current.model.name':(lambda cr, uid, ids, context:ids,['state'],20)})
}
_order = "current_state_num,date desc"

标签：python,openerp,postgresql-8-4
来源： https://codeday.me/bug/20190703/1368510.html