python – 这是正确的tfidf吗？

我试图从文件中获取tfidf.但我不认为它给了我正确的价值观,或者我可能做错了什么.请建议.代码和输出如下：

from sklearn.feature_extraction.text import TfidfVectorizer
books = ["Hello there this is first book to be read by wordcount script.", "This is second book to be read by wordcount script. It has some additionl information.", "just third book."]
vectorizer = TfidfVectorizer()
response = vectorizer.fit_transform(books)
feature_names = vectorizer.get_feature_names()
for col in response.nonzero()[1]:
   print feature_names[col], '-', response[0, col]

更新1 :(由juanpa.arrivillaga建议)

vectorizer = TfidfVectorizer(smooth_idf=False)

输出：

script - 0.269290317245
wordcount - 0.269290317245
by - 0.269290317245
read - 0.269290317245
be - 0.269290317245
to - 0.269290317245
book - 0.209127954024
first - 0.354084405732
is - 0.269290317245
this - 0.269290317245
there - 0.354084405732
hello - 0.354084405732
information - 0.0
...

更新1后的输出：

script - 0.256536760895
wordcount - 0.256536760895
by - 0.256536760895
read - 0.256536760895
be - 0.256536760895
to - 0.256536760895
book - 0.182528018244
first - 0.383055542114
is - 0.256536760895
this - 0.256536760895
there - 0.383055542114
hello - 0.383055542114
information - 0.0
...

根据我的理解,tfidf是= tf * idf.我手动计算它的方式如下：

文档1：“你好,这是第一本由wordcount脚本读取的书.”
文档2：“这是wordcount脚本读取的第二本书.它有一些附加信息.”
文件3：“只是第三本书.”

Tfidf for Hello：

tf= 1/12(total terms in document 1)= 0.08333333333
idf= log(3(total documents)/1(no. of document with term in it))= 0.47712125472
0.08333333333*0.47712125472= 0.03976008865 

这与下面不同(你好 – 0.354084405732).

更新1后手动计算：

tf = 1
idf= log(nd/df) +1 = log (3/1) +1= 0.47712125472 + 1= 1.47712 
tfidf = tf*idf = 1* 1.47712= 1.47712

(与idf平滑后的代码输出“hello – 0.383055542114”不同)

任何有助于了解最新情况的人都非常感谢..

解决方法:

这是没有平滑或标准化的输出：

In [2]: from sklearn.feature_extraction.text import TfidfVectorizer
   ...: books = ["Hello there this is first book to be read by wordcount script.", "This is second book to be read by wordcount sc
   ...: ript. It has some additionl information.", "just third book."]
   ...: vectorizer = TfidfVectorizer(smooth_idf=False, norm=None)
   ...: response = vectorizer.fit_transform(books)
   ...: feature_names = vectorizer.get_feature_names()
   ...: for col in response.nonzero()[1]:
   ...:    print(feature_names[col], '-', response[0, col])
   ...:
hello - 2.09861228867
there - 2.09861228867
this - 1.40546510811
is - 1.40546510811
first - 2.09861228867
book - 1.0
to - 1.40546510811
be - 1.40546510811
read - 1.40546510811
by - 1.40546510811
wordcount - 1.40546510811
script - 1.40546510811
this - 1.40546510811
is - 1.40546510811
book - 1.0
to - 1.40546510811
be - 1.40546510811
read - 1.40546510811
by - 1.40546510811
wordcount - 1.40546510811
script - 1.40546510811
second - 0.0
it - 0.0
has - 0.0
some - 0.0
additionl - 0.0
information - 0.0
book - 1.0
just - 0.0
third - 0.0

所以考虑“你好”的结果：

hello - 2.09861228867

现在,手动：

In [3]: import math

In [4]: tf = 1

In [5]: idf = math.log(3/1) + 1

In [6]: tf*idf
Out[6]: 2.09861228866811

手动计算的问题是您使用的是log base 10,但是您需要使用自然对数.

如果您仍然感觉到要经历平滑和标准化步骤的强烈愿望,那么这应该让您正确地做到这一点.

标签：python,scikit-learn,tf-idf
来源： https://codeday.me/bug/20190627/1306471.html