使用python flask的Slack事件API响应

我正在使用slack事件API.我正在订阅活动上获取活动.
但是如何使用python请求发送响应.几秒钟后,slack再次发回相同的事件
什么json我需要发送回来作为回应停止获得相同的响应？
如果您知道代码,请提前多多谢谢:)

@flask.route("/slack_webhook")
def slack_webhook():
    print("Slack Webhook.....!!!")

    data = json.loads(request.data.decode("utf-8"))
    if 'challenge' in data:
    return(data['challenge'])

    if data['type'] == 'event_callback':
        response = make_response("", 200)
        response.headers['X-Slack-No-Retry'] = 1
        print("returning response")
        return response

    else:
        slack_event_handler.delay(data)

解决方法:

您需要做的就是在3秒内直接使用HTTP 200 OK响应Slack的请求.如果您的应用在该时间内终止,则会自动执行此操作.

如果您需要更多的处理时间,您应该考虑对事件进行排队以便以后处理或启动异步处理.

以下是documentation中的内容：

Your app should respond to the event request with an HTTP 2xx within three seconds. If it does not, we’ll consider the event delivery attempt failed. After a failure, we’ll retry three times, backing off exponentially.

Maintain a response success rate of at least 5% of events per 60 minutes to prevent automatic disabling.

Respond to events with a HTTP 200 OK as soon as you can. Avoid actually processing and reacting to events within the same process. Implement a queue to handle inbound events after they are received.

标签：python,slack-api
来源： https://codeday.me/bug/20190627/1303660.html