python – 使用flask的socketio扩展从线程发出

我想向套接字客户端发出延迟消息.例如,当新客户端连接时,应该向客户端发出“正在检查”消息,并且在一定时间之后应该发出来自线程的另一个消息.

@socket.on('doSomething', namespace='/test')
def onDoSomething(data):
  t = threading.Timer(4, checkSomeResources)
  t.start()
  emit('doingSomething', 'checking is started')

def checkSomeResources()
  # ...
  # some work which takes several seconds comes here
  # ...
  emit('doingSomething', 'checking is done')

但由于上下文问题,代码不起作用.我明白了

RuntimeError('working outside of request context')

是否有可能从线程发出？

解决方法:

问题是线程没有上下文来知道要将消息发送到哪个用户.

您可以将request.namespace作为参数传递给线程,然后使用它发送消息.例：

@socket.on('doSomething', namespace='/test')
def onDoSomething(data):
    t = threading.Timer(4, checkSomeResources, request.namespace)
    t.start()
    emit('doingSomething', 'checking is started')

def checkSomeResources(namespace)
    # ...
    # some work which takes several seconds comes here
    # ...
    namespace.emit('doingSomething', 'checking is done')

标签：python,multithreading,socket-io,flask,flask-socketio
来源： https://codeday.me/bug/20190624/1276027.html