Php使用cURL将映像上传到远程服务器

我想在php中使用cURL将图像上传到远程图像服务器.我有这段代码,它在网络服务器上：

<form enctype="multipart/form-data" encoding="multipart/form-data" method="post" action="webform.php">
<input name="somevar" type=hidden value='.$somevar.'>
<input name="uploadfile" type="file" value="choose">
<input type="submit" value="Upload">
</form>

和：

if (isset($_FILES['uploadfile']) ) {

 $filename  = $_FILES['uploadfile']['tmp_name'];
 $handle    = fopen($filename, "r");
 $data      = fread($handle, filesize($filename));
 $POST_DATA = array(
   'somevar' => $somevar,
   'uploadfile' => $data
 );
 $curl = curl_init();
 curl_setopt($curl, CURLOPT_URL, 'http://1.1.1.1/receiver.php');
 curl_setopt($curl, CURLOPT_TIMEOUT, 30);
 curl_setopt($curl, CURLOPT_POST, 1);
 curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
 curl_setopt($curl, CURLOPT_POSTFIELDS, $POST_DATA);
 $response = curl_exec($curl);
 curl_close ($curl);
 echo $response;

}

在图像服务器上我有一个图像上传处理php文件,它在localhost上工作得很好,但我想在远程服务器上使用它.这是我在receiver.php中处理上传的图像文件的方式：

move_uploaded_file($_FILES['uploadfile']['tmp_name'], $file)

我想直接将图像文件传递给远程服务器脚本,这样我就不需要重写整个上传脚本了.我试图将图像名称,类型,大小发布为帖子变量,但我没有[‘tmp_name’],因为它不在localhost上.

我怎么解决这个问题？谢谢你们的帮助！

解决方法:

这是一个可能的解决方案;

>处理Web服务器上的上传并将上传的文件移动到本地临时位置
>然后向远程服务器发出curl POST请求,并告诉它上传的文件名和内容.数据是; as base64_encoded string
>远程服务器脚本将上载作为标准http帖子接收
>现在要做的就是解码文件数据,将其保存为指定的文件名

所以,这就是解决方案的样子：

对不起,我没有测试这个,但它应该工作.

的index.php

<?php

// Handle upload
if(isset($_POST["submit"]))
{
    // Move uploaded file to a temp location
    $uploadDir = '/var/www/uploads/';
    $uploadFile = $uploadDir . basename($_FILES['userfile']['name']);
    if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadFile))
    {
        // Prepare remote upload data
        $uploadRequest = array(
            'fileName' => basename($uploadFile),
            'fileData' => base64_encode(file_get_contents($uploadFile))
        );

        // Execute remote upload
        $curl = curl_init();
        curl_setopt($curl, CURLOPT_URL, 'http://1.1.1.1/receiver.php');
        curl_setopt($curl, CURLOPT_TIMEOUT, 30);
        curl_setopt($curl, CURLOPT_POST, 1);
        curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
        curl_setopt($curl, CURLOPT_POSTFIELDS, $uploadRequest);
        $response = curl_exec($curl);
        curl_close($curl);
        echo $response;

        // Now delete local temp file
        unlink($uploadFile);
    }
    else
    {
        echo "Possible file upload attack!\n";
    }
}

?>

<!-- The data encoding type, enctype, MUST be specified as below -->
<form enctype="multipart/form-data" action="index.php" method="POST">
    <!-- MAX_FILE_SIZE must precede the file input field -->
    <input type="hidden" name="MAX_FILE_SIZE" value="30000" />
    <!-- Name of input element determines name in $_FILES array -->
    Send this file: <input name="userfile" type="file" />
    <input type="submit" value="Send File" />
</form>

然后,在receiver.php上,您可以执行以下操作：

// Handle remote upload
if (isset($_POST['fileName']) && $_POST['fileData'])
{
    // Save uploaded file
    $uploadDir = '/path/to/save/';
    file_put_contents(
        $uploadDir. $_POST['fileName'],
        base64_decode($_POST['fileData'])
    );

    // Done
    echo "Success";
}

标签：php,curl,remote-server
来源： https://codeday.me/bug/20190623/1270010.html