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python – 找出它是否是闰年并相应地设置

作者:互联网

我有一个具有初始end_date的表单.我有一个价值错误,因为今年是闰年,我们目前在二月.

我的代码有30天的结束日,但我无法弄清楚如何编写代码,如果它是闰年,并将初始end_date设置为2月的正确最后一天.

这是我的forms.py控制end_date初始值

class MaturityLetterSetupForm(forms.Form):
def __init__(self, *args, **kwargs):
    from datetime import datetime
    today = datetime.today()
    start_year = today.year
    start_month = today.month
    start_date = datetime(start_year, start_month, 1)
    try:
        end_date = datetime(start_year, start_month, 30)
    except ValueError:
        end_date = datetime(start_year, start_month, ?)

    super(MaturityLetterSetupForm, self).__init__(*args, **kwargs)
    self.fields['start_date'] = forms.DateField(initial=start_date.strftime("%B %d, %Y"),
        widget=forms.TextInput(attrs={'class':'datepicker', 'value': today }))

    self.fields['end_date'] = forms.DateField(initial=end_date.strftime("%B %d, %Y"),
        widget=forms.TextInput(attrs={'class':'datepicker', 'value': today }))

编辑
与@Paul交谈后
我的初始化成了:

def __init__(self, *args, **kwargs):
    from datetime import datetime
    import calendar
    today = datetime.today()
    start_year = today.year
    start_month = today.month
    start_date = datetime(start_year, start_month, 1)
    if calendar.isleap(start_year) and today.month == 2:
        end_date = datetime(start_year, start_month, calendar.mdays[today.month]+1)
    else:
        end_date = datetime(start_year, start_month, calendar.mdays[today.month])
    super(MaturityLetterSetupForm, self).__init__(*args, **kwargs)
    self.fields['start_date'] = forms.DateField(initial=start_date.strftime("%B %d, %Y"),
        widget=forms.TextInput(attrs={'class':'datepicker', 'value': today }))

    self.fields['end_date'] = forms.DateField(initial=end_date.strftime("%B %d, %Y"),
        widget=forms.TextInput(attrs={'class':'datepicker', 'value': today }))

找到当月的最后一天.

解决方法:

calendar.isleap(year)怎么样?

另外,不要使用try / except来处理这个问题,而是使用if条件.就像是:

if calendar.isleap(year):
    do_stuff
else:
   do_other_stuff

标签:python,django,django-forms,leap-year
来源: https://codeday.me/bug/20190613/1234359.html