c# – 为什么我不能在Windsor中为多个接口注册一个类?
作者:互联网
我正在尝试注册所有实现我的IProcess< T1,T2>的类.与温莎的接口.为此,我在安装程序中有以下代码:
// Register all implemented process interfaces
var procTypes = AppDomain.CurrentDomain
.GetAssemblies()
.SelectMany(x => x.GetTypes())
.Where(x => x.IsDerivedFromOpenGenericType(typeof(IProcess<,>)))
.ToList();
foreach (var procType in procTypes)
foreach (var procInterface in procType.GetInterfaces().Where(x => x.IsDerivedFromOpenGenericType(typeof(IProcess<,>))))
container.Register(Component.For(procInterface).ImplementedBy(procType).LifeStyle.Transient);
我试图注册的一个类是:
public class PositionProcesses
: IProcess<CreatePositionParams, PositionDisplayViewModel>,
IProcess<EditPositionParams, PositionDisplayViewModel>
{
}
第一个接口正确注册,但在注册第二个接口以实现此类时,我收到以下错误:
Test method MyJobLeads.Tests.Controllers.PositionControllerTests.Windsor_Can_Resolve_PositionController_Dependencies threw exception:
Castle.MicroKernel.ComponentRegistrationException: There is a component already registered for the given key MyJobLeads.DomainModel.Processes.Positions.PositionProcesses
在第一次循环迭代中,我的变量是:
+ procInterface {Name = "IProcess`2" FullName = "MyJobLeads.DomainModel.Data.IProcess`2[[MyJobLeads.DomainModel.ProcessParams.Positions.CreatePositionParams, MyJobLeads.DomainModel, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null],[MyJobLeads.DomainModel.ViewModels.Positions.PositionDisplayViewModel, MyJobLeads.DomainModel, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null]]"} System.Type {System.RuntimeType}
+ procType {Name = "PositionProcesses" FullName = "MyJobLeads.DomainModel.Processes.Positions.PositionProcesses"} System.Type {System.RuntimeType}
在第二个:
+ procInterface {Name = "IProcess`2" FullName = "MyJobLeads.DomainModel.Data.IProcess`2[[MyJobLeads.DomainModel.ProcessParams.Positions.EditPositionParams, MyJobLeads.DomainModel, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null],[MyJobLeads.DomainModel.ViewModels.Positions.PositionDisplayViewModel, MyJobLeads.DomainModel, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null]]"} System.Type {System.RuntimeType}
+ procType {Name = "PositionProcesses" FullName = "MyJobLeads.DomainModel.Processes.Positions.PositionProcesses"} System.Type {System.RuntimeType}
(这两个都来自VS调试器.
有任何想法吗?
解决方法:
您应该使用基于约定的组件注册
BasedOnDescriptor processes = AllTypes.FromAssembly(assemblyWithProcesses)
.BasedOn(typeof (IProcess<,>))
.WithService.AllInterfaces()
.Configure(x => x.LifeStyle.Transient);
container.Register(processes)
编辑删除了@ Krzysztof-kozmic提到的第一个样本
标签:c,reflection,castle-windsor 来源: https://codeday.me/bug/20190530/1186127.html