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php – Symfony2.1映射错误:class_parents()

作者:互联网

我试图在Symfony2.1项目中使用Doctrine2从表(通过实体)获取数据时遇到问题.这是我得到错误的控制器:

/**
 * Country list
 */
public function countrylistAction()
{
    $em = $this->getDoctrine()->getManager();
    $countryList = $em->getRepository('ProjectBaseBundle:SYS_TCountry')
        ->findAll();

    $serializer = new Serializer(array(new GetSetMethodNormalizer()),
        array('json' => new JsonEncoder()));

    return new Response($serializer->serialize($countryList, 'json'));
}

实体:

<?php

namespace Company\Project\BaseBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Validator\Constraints as Assert;

/**
 * @ORM\Entity
 * @ORM\Table(name="SYS_TCountry")
 */
class SYS_TCountry
{
    /**
     * @ORM\Id
     * @ORM\Column(type="string", length=3, nullable=false)
     * @var string
     */
    protected $idcountry;

    /**
     * @ORM\Column(type="string", length=75, nullable=false)
     * @Assert\NotBlank()
     * @var string
     */
    protected $name;

    ....

    public function getIdcountry()              { return $this->idcountry; }
    public function getName()                   { return $this->name; }
    public function getA2()                     { return $this->a2; }
    public function getA3()                     { return $this->a3; }
    public function getIdstatus()               { return $this->idstatus; }
    public function setIdcountry($idcountry)    { $this->idcountry = $idcountry; }
    public function setName($name)              { $this->name = $name; }
    public function setA2($a2)                  { $this->a2 = $a2; }
    public function setA3($a3)                  { $this->a3 = $a3; }
    public function setIdstatus($idstatus)      { $this->idstatus = $idstatus; }

    public function __toString()                { return $this->idcountry; }

}

Config.yml:

# Doctrine Configuration
doctrine:
    dbal:
        driver:   %database_driver%
        host:     %database_host%
        port:     %database_port%
        dbname:   %database_name%
        user:     %database_user%
        password: %database_password%
        charset:  UTF8

    orm:
        auto_generate_proxy_classes: %kernel.debug%
        auto_mapping: true

这是错误:

Warning: class_parents(): 
Class Company\Project\BaseBundle\Entity\SYS_TCountry does not exist and could not be loaded in 
/var/www/project/src/vendor/doctrine/common/lib/Doctrine/Common/Persistence/Mapping/RuntimeReflectionService.php line 40

这很奇怪,因为正如Doctrine在控制台中说的那样,映射已经正确完成了:我测试它执行php app / console doctrine:mapping:info:

[OK]   Company\Project\BaseBundle\Entity\SYS_TCountry

如果我在控制台中执行查询一切顺利 – > app / console doctrine:query:sql’SELECT * FROM SYS_TCountry’,返回结果.

我不知道是否使用Symfony2.1我必须配置与2.0版本不同的东西,但似乎是相同的,因为映射是Doctrine的责任.

解决方法:

Symfony遵循PSR-0标准的文件名.除其他外,这意味着如果你在类名中使用下划线,它将在决定你的类应该存在的位置时用目录分隔符替换它,如下所示:

\namespace\package\Class_Name => /path/to/project/lib/vendor/namespace/package/Class/Name.php

所以,如果你有一个名为SYS_TCountry的类,它会期望找到它

Company/Project/BaseBundle/Entity/SYS/TCountry.php

代替

Company/Project/BaseBundle/Entity/SYS_TCountry.php

我认为您最好的解决方案是将文件名和类名更改为SYSTCountry.您无需更改表名称.

标签:php,orm,doctrine,symfony-2-1
来源: https://codeday.me/bug/20190530/1182297.html