c# – 由于一些无效的IL代码,将简单类转换为IL失败了?
作者:互联网
我正在尝试将这个简单的类转换为IL代码:
public class IL {
Dictionary<string, int> props = new Dictionary<string, int>() { {"1",1} };
}
事实上,在尝试使用Emit动态创建类之前,我使用ILDasm来了解IL指令.结果显示:
.class public auto ansi beforefieldinit IL
extends [mscorlib]System.Object
{
.field private class [mscorlib]System.Collections.Generic.Dictionary`2<string,int32> props
.method public hidebysig specialname rtspecialname
instance void .ctor() cil managed
{
//
.maxstack 4
.locals init (class [mscorlib]System.Collections.Generic.Dictionary`2<string,int32> V_0)
IL_0000: ldarg.0
IL_0001: newobj instance void class [mscorlib]System.Collections.Generic.Dictionary`2<string,int32>::.ctor()
IL_0006: stloc.0
IL_0007: ldloc.0
IL_0008: ldstr "1"
IL_000d: ldc.i4.1
IL_000e: callvirt instance void class [mscorlib]System.Collections.Generic.Dictionary`2<string,int32>::Add(!0,
!1)
IL_0013: ldloc.0
IL_0014: stfld class [mscorlib]System.Collections.Generic.Dictionary`2<string,int32> IL::props
IL_0019: ldarg.0
IL_001a: call instance void [mscorlib]System.Object::.ctor()
IL_001f: ret
} // end of method IL::.ctor
} // end of class IL
从那以后,我尝试使用这样的Emit:
var aBuilder = AppDomain.CurrentDomain.DefineDynamicAssembly(new System.Reflection.AssemblyName("test"), AssemblyBuilderAccess.Run);
var mBuilder = aBuilder.DefineDynamicModule("module");
var tBuilder = mBuilder.DefineType("IL");
var field = tBuilder.DefineField("props", typeof(Dictionary<string, int>), System.Reflection.FieldAttributes.Private);
var con = tBuilder.DefineConstructor(System.Reflection.MethodAttributes.Public |
System.Reflection.MethodAttributes.HideBySig |
System.Reflection.MethodAttributes.SpecialName |
System.Reflection.MethodAttributes.RTSpecialName,
System.Reflection.CallingConventions.HasThis, Type.EmptyTypes);
var conIL = con.GetILGenerator();
conIL.Emit(OpCodes.Ldarg_0);
conIL.Emit(OpCodes.Newobj, typeof(Dictionary<string,int>).GetConstructor(Type.EmptyTypes));
conIL.Emit(OpCodes.Stloc_0);
conIL.Emit(OpCodes.Ldloc_0);
conIL.Emit(OpCodes.Ldstr, "1");
conIL.Emit(OpCodes.Ldc_I4_1);
conIL.Emit(OpCodes.Callvirt, typeof(Dictionary<string, int>).GetMethod("Add"));
conIL.Emit(OpCodes.Ldloc_0);
conIL.Emit(OpCodes.Stfld, field);
conIL.Emit(OpCodes.Ldarg_0);
conIL.Emit(OpCodes.Call, typeof(object).GetConstructor(Type.EmptyTypes));
conIL.Emit(OpCodes.Ret);
现在尝试使用它:
var t = tBuilder.CreateType();
var instance = Activator.CreateInstance(t);//exception has been thrown here
//saying "Common Language Runtime detected an invalid program."
这意味着IL代码在某些时候会出错.但是将它与ILDasm实际生成的内容进行比较,我认为没有任何区别.这有什么不对?
解决方法:
您错过了声明IL_0006,IL_0007和IL_0013行中引用的局部变量.添加以下行,它将起作用.
conIL.DeclareLocal(typeof (Dictionary<string, int>), false);
很可能这个本地是由编译器引入的,因为代码是在调试模式下编译的.
标签:c,dynamic,reflection,reflection-emit,il 来源: https://codeday.me/bug/20190516/1117039.html