JGUI源码：实现图标按钮及下拉菜单(16)

效果如下

代码片段如下

<div class="jgui-btn" id="personalbtn" style="float:right;">
                <div class="jgui-btn-info">
                    <img src="./images/head.jpg"></img>
                    <span>麦田守望者</span>
                    <i class="jgui-btn-down"></i>
                </div>
                <div class="jgui-menu" id="testmenu">
                    <div class="jgui-menuitem off">切换用户</div>
                    <div class="jgui-menuitem exit">退出系统</div> 
                </div>
            </div>

//用户事件
  $("#personalbtn").unbind('click').click(function ()
  {
      
      var $this=$(this);
      var $btnmenu=$this.find('.jgui-menu');
      //显示菜单
      $btnmenu.css("top",$this.position().top+$this.height());
      $btnmenu.css("left",$this.position().left);
      $btnmenu.css("right",10);
      $btnmenu.css("visibility","visible");
      $btnmenu.find('.closecurtab').unbind("click").click(function(event){
      $this.find(".jgui-tab-close").first().trigger("click");
      });
      //关闭其它
      $btnmenu.find('.off').unbind("click").click(function(event){
        alert('点击了切换用户');
      });
      //关闭左边
      $btnmenu.find('.exit').unbind("click").click(function(event){
        alert('点击了退出系统');
      });
      return false; 
  });

标签：function,unbind,btnmenu,16,下拉菜单,find,源码,click,css
来源： https://www.cnblogs.com/zhaogaojian/p/10534376.html