UVA227 Puzzle(C++)
作者:互联网
- 题目链接
- 注意点:
(1) 输出的时候注意相邻两个案例之间要有空行
(2) 输出的字符不要包含中文标点
- 代码
#include <iostream>
#include <string.h>
using namespace std;
int main(int argc, char *argv[])
{
int puzzleNum = 1; //计数
string operate; //存储具体操作 (ABLR)
while(1)
{
string str[5];
/* 1. 数据预处理 */
getline(cin, str[0]);
if(str[0] == "Z") break;
if(puzzleNum != 1) cout<<endl;
for(int i = 1; i < 5; i++) getline(cin, str[i]);
string s;
operate = "";
while(1)
{
getline(cin, s);
operate += s;
if(s[s.length()-1] == '0') break;
}
/* 2. 找出空格位置 */
int x,y; //空格的位置
for(int i = 0; i < 5; i++)
for(int j = 0; j < 5; j++)
{
if(str[i][j] == ' ')
{
x = i;
y = j;
goto L;
}
}
L:
/* 3. 模拟操作 */
bool b = 1; //判断最终有没有成功
int xx, yy;
for(int i = 0; i < operate.length()-1; i++)
{
xx = x; yy = y; //存储该步操作之前的位置
if(operate[i] == 'A') x--;
if(operate[i] == 'B') x++;
if(operate[i] == 'L') y--;
if(operate[i] == 'R') y++;
// 判断操作合法性
if(x == -1 || y == -1 || x == 5 || y == 5)
{
b = 0;
break;
}
// 执行操作步骤
str[xx][yy] = str[x][y];
str[x][y] = ' ';
}
/* 4. 输出 */
cout<<"Puzzle #"<<puzzleNum++<<":"<<endl;
if(b)
{
for(int i = 0; i < 5; i++)
cout<<str[i][0]<<" "<<str[i][1]<<" "<<str[i][2]<<" "<<str[i][3]<<" "<<str[i][4]<<endl;
}
else
cout<<"This puzzle has no final configuration."<<endl;
}
return 0;
}
标签:输出,UVA227,string,int,Puzzle,C++,str,include,puzzleNum 来源: https://blog.csdn.net/cxzs110/article/details/88528976