Python函数指定参数、返回值类型{def fun(arg: str) -> str:}
作者:互联网
def as_view(name: str, *class_args: int, **class_kwargs: str) -> int: return int(name) + class_args[1] + int(class_kwargs['k1']) print(as_view('1', 2, 3, 4, k1='5', k2='6')) print(type(as_view('1', 2, 3, 4, k1='5', k2='6'))) print(str(as_view('1', 2, 3, 4, k1='5', k2='6'))) print(type(str(as_view('1', 2, 3, 4, k1='5', k2='6'))))
9 <class 'int'> 9 <class 'str'>
标签:int,Python,print,k2,k1,str,fun,view 来源: https://www.cnblogs.com/ailiailan/p/16213655.html