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Python函数指定参数、返回值类型{def fun(arg: str) -> str:}

作者:互联网

def as_view(name: str, *class_args: int, **class_kwargs: str) -> int:
    return int(name) + class_args[1] + int(class_kwargs['k1'])

print(as_view('1', 2, 3, 4, k1='5', k2='6'))

print(type(as_view('1', 2, 3, 4, k1='5', k2='6')))

print(str(as_view('1', 2, 3, 4, k1='5', k2='6')))

print(type(str(as_view('1', 2, 3, 4, k1='5', k2='6'))))
9
<class 'int'>
9
<class 'str'>

 

标签:int,Python,print,k2,k1,str,fun,view
来源: https://www.cnblogs.com/ailiailan/p/16213655.html