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Python的cmp_to_key()函数详解【部分翻译+leetcode题目分析】

作者:互联网

定义

示例 1:使用 cmp_to_key() 函数提供的键对列表进行排序的程序

import functools


def mycmp(a, b):
	print("comparing ", a, " and ", b)
	if a > b:
		return 1
	elif a < b:
		return -1
	else:
		return 0


print(sorted([1, 2, 4, 2], key=functools.cmp_to_key(mycmp)))

输出:

comparing  2  and  1
comparing  4  and  2
comparing  2  and  4
comparing  2  and  2
comparing  2  and  4
[1, 2, 2, 4]

示例 2:使用 cmp_to_key() 函数提供的键从列表中打印最大和最小数字的程序

import functools


def mycmp(a, b):
	print("comparing ", a, " and ", b)
	if a > b:
		return 1
	elif a < b:
		return -1
	else:
		return 0


print(min([45, 78, 813], key=functools.cmp_to_key(mycmp)))
print(max([45, 78, 813], key=functools.cmp_to_key(mycmp)))

输出:

comparing  78  and  45
comparing  813  and  45
45
comparing  78  and  45
comparing  813  and  78
813

-------------------------------------------------------以下是leetcode题目-----------------------------------------------

解决方法:

class Solution:
    def largestNumber(self, nums):
        def cmp_func(x, y):
            if x + y > y + x:
                return 1
            elif x == y:
                return 0
            else:
                return -1
        nums = [str(num) for num in nums]
        nums.sort(key = cmp_to_key(cmp_func), reverse = True)
        return ''.join(nums).lstrip('0') or '0'

标签:return,Python,functools,45,comparing,key,leetcode,cmp
来源: https://blog.csdn.net/Father_of_Python/article/details/123118854