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python两个字符串有变化值作对比

作者:互联网

 1 def replace_star(actual, expect):
 2     count = 0
 3     for expect_char in expect:
 4         count += 1
 5         if expect_char == '*':  # 遍历预期字符串,找到*位置
 6             actual = actual[:count - 1] + "*" + actual[count:]  # 把实际字符串该位置替换为*
 7             for actual_char in actual[count:]:
 8                 if actual_char == '"':  # 依次替换后面的字符为空,直到引号,引号可以换为其他字符,亦可多个
 9                     break
10                 actual = actual[:count] + actual[count + 1:]
11     return actual
12 
13 if __name__ == '__main__':
14     actual = '{"Status": 1, "Content": {"order_no": "20190813173142658002396779806585", "request_id": "4999870244479602310", "status": "SUCCESS"}, "Message": "请求成功"}'
15     expect = '{"Status": 1, "Content": {"order_no": "*", "request_id": "*", "status": "SUCCESS"}, "Message": "请求成功"}'
16 
17     actual = replace_star(actual, expect)
18     print(actual)

两个字符串作对比,实际值一些no变化,预期值中用*代替

标签:count,__,actual,no,python,值作,char,expect,字符串
来源: https://www.cnblogs.com/yuminhu/p/15619262.html