如何在python中使用SPARQLWrapper处理参数化查询中的字符串
作者:互联网
from SPARQLWrapper import SPARQLWrapper, RDFXML, JSON, XML, N3 from rdflib import Graph sparql = SPARQLWrapper("https://agrovoc.uniroma2.it/sparql") sparql.setQuery(""" PREFIX skos: <http://www.w3.org/2004/02/skos/core#> PREFIX skosxl: <http://www.w3.org/2008/05/skos-xl#> SELECT * WHERE { ?subject a skos:Concept . ?subject skosxl:prefLabel ?xLab . ?xLab skosxl:literalForm "biomass"@en . } """) sparql.setReturnFormat(JSON) results = sparql.query().convert() print(results)
pip install SPARQLWrapper
标签:xLab,sparql,python,SPARQLWrapper,PREFIX,字符串,skosxl,skos 来源: https://www.cnblogs.com/Mint-diary/p/15577108.html