112. 路径总和 Java版

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public boolean hasPathSum(TreeNode root, int targetSum) {

        if(root == null)
            return false;

        if(root.left == null && root.right == null)
            return targetSum-root.val == 0;

        return hasPathSum(root.left,targetSum - root.val) || hasPathSum(root.right,targetSum - root.val);

    }
}

标签：right,TreeNode,val,int,112,Java,left,root,总和
来源： https://blog.csdn.net/CSDNer_zry/article/details/120613710