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[ARM-assembly]-汇编示例:c语言翻译成汇编

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示例1:

int func_test(uint32_t a, uint32_t b, uint32_t *s)
{
	*s = a + b;
	return 0;
}

00000000002047a0 <func_test>:
  2047a0:	0b010000 	add	w0, w0, w1
  2047a4:	b9000040 	str	w0, [x2]
  2047a8:	52800000 	mov	w0, #0x0                   	// #0
  2047ac:	d65f03c0 	ret

示例2

int func_memcpy(void *a, void *b, uint32_t len)
{
	memcpy(a,b,len);
	return 0;
}

int func_test(uint32_t integer1, uint32_t integer2, uint32_t *p_integer)
{
	char a[128];
	*p_integer = integer1 + integer2;

	func_memcpy(a,"testtesttesttesttesttest",*p_integer);
	return 0;
}
数据段中的:"testtesttesttesttesttest"
  215430:	6f697372 7325206e 6574000a 65747473     rsion %s..testte
  215440:	65747473 65747473 65747473 65747473     sttesttesttestte
  215450:	76007473 69737265 25206e6f 64252c64     st.version %d,%d

00000000002047a0 <func_test>:
  2047a0:	a9b77bfd 	stp	x29, x30, [sp,#-144]!
  2047a4:	0b010000 	add	w0, w0, w1
  2047a8:	b0000081 	adrp	x1, 215000 <build_message+0x2a0>
  2047ac:	910003fd 	mov	x29, sp
  2047b0:	b9000040 	str	w0, [x2]
  2047b4:	9110e821 	add	x1, x1, #0x43a
  2047b8:	2a0003e2 	mov	w2, w0
  2047bc:	910043a0 	add	x0, x29, #0x10
  2047c0:	94003d7d 	bl	213db4 <memcpy>
  2047c4:	52800000 	mov	w0, #0x0                   	// #0
  2047c8:	a8c97bfd 	ldp	x29, x30, [sp],#144
  2047cc:	d65f03c0 	ret

由此看来,这是一个递减的栈.
(1)
stp x29, x30, [sp,#-144]! //sp=sp-144后,将x29和x30拷贝到sp中,即:
0到-128是数组变量a,-129到-144是 x29和x30(lr)。 这里其实就是保存x29和x30
(2)
add x0, x29, #0x10 //x29是当前的栈地址(sp),sp+0x10正好就是数组a的地址,这句就是将数组a的地址拷贝到x0中
(3)ldp x29, x30, [sp],#144 从sp处拷贝两个double-world到x29和x30,这里其实就是恢复x29和x30。 拷贝之后,再sp=sp+144

标签:汇编,x30,assembly,示例,sp,144,x29,w0,uint32
来源: https://blog.51cto.com/u_15278218/2930991