多线程练习-熊吃蜂蜜

要求

现在有一个罐子，两只熊，十只蜜蜂，每只蜜蜂每隔十秒产生一滴蜂蜜，熊大一次吃5滴蜂蜜，熊二一次吃10滴蜂蜜，吃完就不吃了。

实现

罐子的实现

static class Contanier {
        private int honey;

        public Contanier() {

        }

        public void add() {
            synchronized (Contanier.class) {
                honey += 1;
            }
        }

        public Boolean eat(int appetite) {
            synchronized (Contanier.class) {
                if (honey / appetite > 0) {
                    honey -= appetite;
                    return true;
                } else {
                    return false;
                }
            }
        }
    }

熊

 static class Bear implements Runnable {

        private int appetite;

        private Contanier contanier;

        Boolean eated = false;

        public Bear(Contanier contanier, int appetite) {
            this.contanier = contanier;
            this.appetite = appetite;
        }

        @Override
        public void run() {
            while (!eated) {
                eated = contanier.eat(appetite);
                if (eated) {
                    System.out.println("熊" + Thread.currentThread().getName() + "吃到蜂蜜了，终止线程");
                }
            }
        }
    }

小蜜蜂

 static class Bee implements Runnable {
        private Contanier contanier;

        public Bee(Contanier contanier) {
            this.contanier = contanier;
        }

        @Override
        public void run() {
            while (true){
                try {
                    Thread.sleep(10000);
                    contanier.add();
                    System.out.println("小蜜蜂"+Thread.currentThread().getName() +"生产了蜂蜜");
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
        }
    }

执行方法

public static void main(String[] args) {
       Contanier contanier = new Contanier();
       for (int i= 0; i< 10; i++){
           Thread thread = new Thread(new Bee(contanier), ""+i);
           thread.start();
       }
        Thread bear1 = new Thread(new Bear(contanier,5), "大");
        bear1.start();
        Thread bear2 = new Thread(new Bear(contanier, 10), "二");
        bear2.start();
    } 

运行效果

标签：contanier,Thread,Contanier,蜂蜜,new,appetite,多线程,public,熊吃
来源： https://blog.csdn.net/weixin_43125410/article/details/116701313