报时助手
作者：互联网
报时助手
题目正文
给定当前的时间，请用英文的读法将它读出来。
时间用时h和分m表示，在英文的读法中，读一个时间的方法是：
如果m为0，则将时读出来，然后加上“o’clock”，如3:00读作“three o’clock”。
如果m不为0，则将时读出来，然后将分读出来，如5:30读作“five thirty”。
时和分的读法使用的是英文数字的读法，其中0~20读作：
0:zero 1: one 2:two 3:three 4:four 5:five 6:six 7:seven 8:eight 9:nine 10:ten 11:eleven 12:twelve
13:thirteen 14:fourteen 15:fifteen 16:sixteen 17:seventeen 18:eighteen 19:nineteen 20:twenty。
30读作thirty，40读作forty，50读作fifty。
对于大于20小于60的数字，首先读整十的数，然后再加上个位数。如31首先读30再加1的读法，读作“thirty one”。
按上面的规则21:54读作“twenty one fifty four”，9:07读作“nine seven”，0:15读作“zero fifteen”。
输入
输入包含两个非负整数h和m，表示时间的时和分。非零的数字前没有前导0。h小于24，m小于60。
输出
输出时间时刻的英文。
样例
0 15
zero fifteen
代码如下：
#include<stdio.h>
#include<iostream>
using namespace std;
int hours(int h)
{
switch(h)
{
case 0:
cout<<"zero o'clock";break;
case 1:
cout<<"one o'clock";break;
case 2:
cout<<"two o'clock";break;
case 3:
cout<<"three o'clock";break;
case 4:
cout<<"four o'clock";break;
case 5:
cout<<"five o'clock";break;
case 6:
cout<<"six o'clock";break;
case 7:
cout<<"seven o'clock";break;
case 8:
cout<<"eight o'clock";break;
case 9:
cout<<"nine o'clock";break;
case 10:
cout<<"ten o'clock";break;
case 11:
cout<<"eleven o'clock";break;
case 12:
cout<<"twelve o'clock";break;
case 13:
cout<<"thirteen o'clock";break;
case 14:
cout<<"fourteen o'clock";break;
case 15:
cout<<"fifteen o'clock";break;
case 16:
cout<<"sixteen o'clock";break;
case 17:
cout<<"seventeen o'clock";break;
case 18:
cout<<"eighteen o'clock";break;
case 19:
cout<<"nineteen o'clock";break;
case 20:
cout<<"twenty o'clock";break;
case 21:
cout<<"twenty one o'clock";break;
case 22:
cout<<"twenty two o'clock";break;
case 23:
cout<<"twenty three o'clock";break;
}
}
int minutes(int m)
{
if(m>=0 && m<=20)
{
switch(m)
{
case 0:
cout<<"zero"<<endl;break;
case 1:
cout<<"one"<<endl;break;
case 2:
cout<<"two"<<endl;break;
case 3:
cout<<"three"<<endl;break;
case 4:
cout<<"four"<<endl;break;
case 5:
cout<<"five"<<endl;break;
case 6:
cout<<"six"<<endl;break;
case 7:
cout<<"seven"<<endl;break;
case 8:
cout<<"eight"<<endl;break;
case 9:
cout<<"nine"<<endl;break;
case 10:
cout<<"ten"<<endl;break;
case 11:
cout<<"eleven"<<endl;break;
case 12:
cout<<"twelve"<<endl;break;
case 13:
cout<<"thirteen"<<endl;break;
case 14:
cout<<"fourteen"<<endl;break;
case 15:
cout<<"fifteen"<<endl;break;
case 16:
cout<<"sixteen"<<endl;break;
case 17:
cout<<"seventeen"<<endl;break;
case 18:
cout<<"eighteen"<<endl;break;
case 19:
cout<<"nineteen"<<endl;break;
case 20:
cout<<"twenty"<<endl;break;
}
}
else if(m>=20 &&m<=60)
{
switch(m/10)
{
case 2:
cout<<"twenty ";minutes(m%10);break;
case 3:
cout<<"thirty ";minutes(m%10);break;
case 4:
cout<<"forty ";minutes(m%10);break;
case 5:
cout<<"fifty ";minutes(m%10);break;
}
}
}
int hm(int h)
{
switch(h)
{
case 0:
cout<<"zero ";break;
case 1:
cout<<"one ";break;
case 2:
cout<<"two ";break;
case 3:
cout<<"three ";break;
case 4:
cout<<"four ";break;
case 5:
cout<<"five ";break;
case 6:
cout<<"six ";break;
case 7:
cout<<"seven ";break;
case 8:
cout<<"eight ";break;
case 9:
cout<<"nine ";break;
case 10:
cout<<"ten ";break;
case 11:
cout<<"eleven ";break;
case 12:
cout<<"twelve ";break;
case 13:
cout<<"thirteen ";break;
case 14:
cout<<"fourteen ";break;
case 15:
cout<<"fifteen ";break;
case 16:
cout<<"sixteen ";break;
case 17:
cout<<"seventeen ";break;
case 18:
cout<<"eighteen ";break;
case 19:
cout<<"nineteen ";break;
case 20:
cout<<"twenty ";break;
case 21:
cout<<"twenty one ";break;
case 22:
cout<<"twenty two ";break;
case 23:
cout<<"twenty three ";break;
}
}
int main()
{
int h,m;
cin>>h>>m;
if(m==0)
hours(h);
else if(m!=0)
{
hm(h);
minutes(m);
}
return 0;
}
总结
这题是一道简单的输出题目，只需要注意的是当分钟大于20小于60时，应该调用它本身，我是自定义了三个函数，分别用于是整点时和不是整点时，输出时注意格式即可。
标签：case,20,cout,读法,switch,读作,助手,报时 来源： https://blog.csdn.net/MarigoldLi/article/details/116356223