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694. Number of Distinct Islands

作者:互联网

Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) connected 4-directionally (horizontal or vertical.) You may assume all four edges of the grid are surrounded by water.

Count the number of distinct islands. An island is considered to be the same as another if and only if one island can be translated (and not rotated or reflected) to equal the other.

Example 1:

11000
11000
00011
00011

Given the above grid map, return 1.

 

Example 2:

11011
10000
00001
11011

Given the above grid map, return 3.

Notice that:

11
1

and

 1
11

are considered different island shapes, because we do not consider reflection / rotation.

 1 class Solution {
 2     int[][] dirs = new int[][] { { 1, 0 }, { 0, 1 }, { -1, 0 }, { 0, -1 } };
 3     public int numDistinctIslands(int[][] grid) {
 4         Set<String> set = new HashSet<>();
 5         int res = 0;
 6 
 7         for (int i = 0; i < grid.length; i++) {
 8             for (int j = 0; j < grid[0].length; j++) {
 9                 if (grid[i][j] == 1) {
10                     StringBuilder sb = new StringBuilder();
11                     helper(grid, i, j, 0, 0, sb);
12                     String s = sb.toString();
13                     if (!set.contains(s)) {
14                         res++;
15                         set.add(s);
16                     }
17                 }
18             }
19         }
20         return res;
21     }
22 
23     public void helper(int[][] grid, int i, int j, int xpos, int ypos, StringBuilder sb) {
24         grid[i][j] = 0;
25         sb.append(xpos + "" + ypos);
26         for (int[] dir : dirs) {
27             int x = i + dir[0];
28             int y = j + dir[1];
29             if (x < 0 || y < 0 || x >= grid.length || y >= grid[0].length || grid[x][y] == 0)
30                 continue;
31             helper(grid, x, y, xpos + dir[0], ypos + dir[1], sb);
32         }
33     }
34 }

 

标签:Distinct,island,Number,int,length,grid,sb,Islands,dir
来源: https://www.cnblogs.com/beiyeqingteng/p/14630651.html