关于*和&的数组操作运算对比(三维数组)

code

#include <stdio.h>
int main(void)
{
    int a[2][3][4]={  5, 10, 15, 20, 
                     25, 30, 35, 40,
                     45, 50, 55, 60,

                     65, 70, 75, 80,
                     85, 90, 95,105,
                    110,115,120,125};

    printf("       a=%08x\n",  a);
    printf("     a+1=%08x\n\n",  a+1);

    printf("      *a=%08x\n", *a);
    printf("    *a+1=%08x\n\n", *a+1);

    printf("     **a=%08x\n",**a);
    printf("   **a+1=%08x\n\n", **a+1);

    printf("    ***a=%08x\n",***a);
    printf("  ***a+1=%08x\n\n", ***a+1);

    printf("      &a=%08x\n", &a);
    printf("    &a+1=%08x\n\n\n\n\n\n", &a+1);

    printf("    %08x    ",&a[0][0][0]);
    printf("%08x    ",&a[0][0][1]);
    printf("%08x    ",&a[0][0][2]);
    printf("%08x\n\n",&a[0][0][3]);

    printf("    %08x    ",&a[0][1][0]);
    printf("%08x    ",&a[0][1][1]);
    printf("%08x    ",&a[0][1][2]);
    printf("%08x\n\n",&a[0][1][3]);

    printf("    %08x    ",&a[0][2][0]);
    printf("%08x    ",&a[0][2][1]);
    printf("%08x    ",&a[0][2][2]);
    printf("%08x\n\n",&a[0][2][3]);

    printf("    %08x    ",&a[1][0][0]);
    printf("%08x    ",&a[1][0][1]);
    printf("%08x    ",&a[1][0][2]);
    printf("%08x\n\n",&a[1][0][3]);

    printf("    %08x    ",&a[1][1][0]);
    printf("%08x    ",&a[1][1][1]);
    printf("%08x    ",&a[1][1][2]);
    printf("%08x\n\n",&a[1][1][3]);

    printf("    %08x    ",&a[1][2][0]);
    printf("%08x    ",&a[1][2][1]);
    printf("%08x    ",&a[1][2][2]);
    printf("%08x\n\n",&a[1][2][3]);

    getchar();
    return 0;
} 

运算结果

总结：

1.a+1与a的差值为       3元素*4元素*4字节=48.

2.*a+1与*a的差值为           4元素*4字节=16.

3.**a+1与**a的差值为         1元素*4字节=4

标签：08x,字节,int,元素,三维,差值,数组,printf,运算
来源： https://www.cnblogs.com/kunshanpipixia/p/14608978.html