1213. Intersection of Three Sorted Arrays
作者:互联网
Given three integer arrays arr1
, arr2
and arr3
sorted in strictly increasing order, return a sorted array of only the integers that appeared in all three arrays.
Example 1:
Input: arr1 = [1,2,3,4,5], arr2 = [1,2,5,7,9], arr3 = [1,3,4,5,8] Output: [1,5] Explanation: Only 1 and 5 appeared in the three arrays.
Example 2:
Input: arr1 = [197,418,523,876,1356], arr2 = [501,880,1593,1710,1870], arr3 = [521,682,1337,1395,1764] Output: []
1 class Solution { 2 public List<Integer> arraysIntersection(int[] arr1, int[] arr2, int[] arr3) { 3 int a = 0, b = 0, c = 0; 4 List<Integer> res = new ArrayList<>(); 5 while (a < arr1.length && b < arr2.length && c < arr3.length) { 6 int min = Math.min(arr1[a], Math.min(arr2[b], arr3[c])); 7 if (arr1[a] == min && arr2[b] == min && arr3[c] == min) res.add(min); 8 if (arr1[a] == min) a++; 9 if (arr2[b] == min) b++; 10 if (arr3[c] == min) c++; 11 } 12 return res; 13 } 14 }
标签:1213,&&,min,Arrays,int,arr3,arr2,arr1,Intersection 来源: https://www.cnblogs.com/beiyeqingteng/p/14528696.html