PAT甲级 1004 Counting Leaves (30 分)

题目

分析

想着试试 最近用的BFS算法 加上队列 然后就ac了 代码有待优化 但看了下结果感觉还挺快的

code

#include <stdio.h>
#include <iostream>
#include <vector>
#include <queue>
using namespace std;
struct Node
{
    int sun;
    int lnum;
    vector<int> leafs;
} nodes[110];
int main()
{
    int all, left;
    cin >> all >> left;
    for (int i = 0; i < left; i++)
    {
        int curr, num;
        cin >> curr >> num;
        Node node;
        node.lnum = num;
        vector<int> leaff;
        for (int j = 0; j < num; j++)
        {
            int tmp;
            cin >> tmp;
            nodes[tmp].sun = 1;
            leaff.push_back(tmp);
        }
        node.leafs = leaff;
        nodes[curr] = node;
    }
    queue<int> q;
    q.push(1);
    int currlevel = 1;
    int currnum = 1;
    int res[110] = {0};
    while (!q.empty())
    {
        int a = q.front();
        q.pop();
        Node fnode = nodes[a];
        currnum--;
        if(fnode.lnum==0){
            res[currlevel]++;
        }
        for (int i = 0; i < fnode.lnum; i++)
        {
            q.push(fnode.leafs[i]);
        }
        if(currnum == 0){
            currnum = q.size();
            currlevel++;
        }
    }
    for (int i = 1; i < currlevel; i++)
    {
        if(i!=1) cout<<" ";
        cout<<res[i];
    }
    
}

结果

标签：PAT,int,Leaves,currlevel,++,num,currnum,nodes,1004
来源： https://blog.csdn.net/wenzhouxiaomayi77/article/details/113761743