抓取分析测试
作者:互联网
public void Pick_Down(double[] pointt1, double[] pointt2, double[] pointt3) { Trajectory_yuanhu.trajectory_s(pointt1, pointt2); int Row; Row = Trajectory_yuanhu.Nn + 1; double[,] B11 = new double[Row, 3]; double[,] B12 = new double[Row, 3]; double[,] B13 = new double[Row, 3]; Point_Down(pointt1, pointt2); //将轨迹对应的逆解求出 for (int i = 0; i < Row; i = i + 1) { B11[i, 0] = Inverse.B1[i, 0]; B11[i, 1] = Inverse.B1[i, 1]; B11[i, 2] = Inverse.B1[i, 2]; } Point_Down(pointt2, pointt3); for (int i = 0; i < Row; i = i + 1) { B12[i, 0] = Inverse.B1[i, 0]; B12[i, 1] = Inverse.B1[i, 1]; B12[i, 2] = Inverse.B1[i, 2]; } Point_Down(pointt3, pointt1); for (int i = 0; i < Row; i = i + 1) { B13[i, 0] = Inverse.B1[i, 0]; B13[i, 1] = Inverse.B1[i, 1]; B13[i, 2] = Inverse.B1[i, 2]; } double speed = gear * decimal.ToDouble(run_speed.Value) * (fp / (2 * Math.PI)); //单位:unit/s LTSMC.smc_conti_set_lookahead_mode(CardNum, 0, 0, 0, 0, 0); LTSMC.smc_conti_open_list(CardNum, 0, 3, axis_all); LTSMC.smc_set_vector_profile_unit(CardNum, 0, speed, speed, acc / 2, dec / 2, speed);//设置插补运动速度参数 LTSMC.smc_set_vector_s_profile(CardNum, 0, 0, acc / 2);//设置s曲线平滑时间 LTSMC.smc_conti_change_speed_ratio(CardNum, 0, 0.5); LTSMC.smc_conti_line_unit(CardNum, 0, 3, axis_all, new double[] { B11[0, 0], B11[0, 1], B11[0, 2] }, 1, 0);//运动模式,0: 相对坐标模式, 1: 绝对坐标模式 int xh = 1; while (xh < 20) { // LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); LTSMC.smc_conti_write_outbit(CardNum, 0, 15, 0, 0); LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); for (int i = 0; i < Row; i = i + 1) { LTSMC.smc_conti_line_unit(CardNum, 0, 3, axis_all, new double[] { B11[i, 0], B11[i, 1], B11[i, 2] }, 1, 0);//运动模式,0: 相对坐标模式, 1: 绝对坐标模式 } // LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); LTSMC.smc_conti_write_outbit(CardNum, 0, 15, 1, 0); LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); for (int i = 0; i < Row; i = i + 1) { LTSMC.smc_conti_line_unit(CardNum, 0, 3, axis_all, new double[] { B12[i, 0], B12[i, 1], B12[i, 2] }, 1, 0);//运动模式,0: 相对坐标模式, 1: 绝对坐标模式 } // LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); LTSMC.smc_conti_write_outbit(CardNum, 0, 15, 0, 0); LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); for (int i = 0; i < Row; i = i + 1) { LTSMC.smc_conti_line_unit(CardNum, 0, 3, axis_all, new double[] { B13[i, 0], B13[i, 1], B13[i, 2] }, 1, 0);//运动模式,0: 相对坐标模式, 1: 绝对坐标模式 } // LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); LTSMC.smc_conti_write_outbit(CardNum, 0, 15, 1, 0); LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); for (int i = 0; i < Row; i = i + 1) { LTSMC.smc_conti_line_unit(CardNum, 0, 3, axis_all, new double[] { B11[i, 0], B11[i, 1], B11[i, 2] }, 1, 0);//运动模式,0: 相对坐标模式, 1: 绝对坐标模式 } // LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); LTSMC.smc_conti_write_outbit(CardNum, 0, 15, 0, 0); LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); for (int i = 0; i < Row; i = i + 1) { LTSMC.smc_conti_line_unit(CardNum, 0, 3, axis_all, new double[] { B12[i, 0], B12[i, 1], B12[i, 2] }, 1, 0);//运动模式,0: 相对坐标模式, 1: 绝对坐标模式 } // LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); LTSMC.smc_conti_write_outbit(CardNum, 0, 15, 1, 0); LTSMC.smc_conti_delay(CardNum, 0, 0.1, 0); for (int i = 0; i < Row; i = i + 1) { LTSMC.smc_conti_line_unit(CardNum, 0, 3, axis_all, new double[] { B13[i, 0], B13[i, 1], B13[i, 2] }, 1, 0);//运动模式,0: 相对坐标模式, 1: 绝对坐标模式 } xh = xh + 1; } LTSMC.smc_conti_start_list(CardNum, 0);//启动插补 LTSMC.smc_conti_close_list(CardNum, 0);//关闭插补缓冲区 } //将两点的轨迹离散 public void Point_Down(double[] pointtt1, double[] pointtt2) { Trajectory_yuanhu.trajectory_s(pointtt1, pointtt2); int Row; Row = Trajectory_yuanhu.Nn + 1; double[] GX = new double[Row]; double[] GY = new double[Row]; double[] GZ = new double[Row]; double[] V1 = new double[Row]; double[] V2 = new double[Row]; double[] V3 = new double[Row]; double[,] D1 = new double[Row, 3]; for (int j = 0; j < Row; j++) { GX[j] = Trajectory_yuanhu.ss[j, 0]; GY[j] = Trajectory_yuanhu.ss[j, 1]; GZ[j] = Trajectory_yuanhu.ss[j, 2]; //把离散的轨迹点存放到 // S_v[j] = Trajectory_yuanhu.G_v[j]; //离散的轨迹点所对应的速度 } Inverse.inverse_run(GX, GY, GZ); }
标签:double,LTSMC,conti,抓取,CardNum,分析测试,smc,Row 来源: https://www.cnblogs.com/charles48789982/p/14348721.html