（第三次上机）已知一个矩阵，储存在一个二维数组中。将矩阵中和值最大的那一行元素与首行对换。

在这里插入代码片
#include<iostream>
using namespace std;
int main()
{   
	int arr[5][5]{
		{1,2,3,4,5},
		{2,3,4,5,6},
		{3,4,5,6,7},
		{1,1,1,1,1},
		{2,2,2,2,2}
	};
	int arr2[5];
	for (int i = 0; i < 5; i++) {
		int sum = 0;
		for (int j = 0; j < 5; j++) {
			sum += arr[i][j];
		}
		arr2[i] = sum;
	}
	int max = arr2[0];
	for (int i = 0; i < 5; i++) {
		if (max < arr2[i]) {
			max = arr2[i];
		}
	}
	int t[3][5];
	for (int i = 0; i < 5; i++) {
		if (max == arr2[i]) {
			for (int j = 0; j < 5;j++) {
			    t[0][j] = arr[0][j];
				arr[0][j] = arr[i][j];
				arr[i][j] = t[0][j];
			}
		}
	}
	for (int i = 0; i < 5; i++) {
		for (int j = 0; j < 5; j++) {
			cout << arr[i][j];
		}
		cout << endl;
	}
	return 0;
}

标签：arr,int,矩阵,sum,对换,首行,++,arr2,max
来源： https://blog.csdn.net/qq_51720038/article/details/110732835