leetcode-289-生命游戏
作者:互联网
解法一:O(MN)O(MN))Java版
class Solution { public void gameOfLife(int[][] board) { int [] neighbors = {0,1,-1}; int rows = board.length; int cols = board[0].length; int [][] copyBoard = new int [rows][cols]; for(int row = 0;row<rows;row++){ for(int col = 0;col< cols; col++){ copyBoard[row][col] = board[row][col]; } } for(int row = 0; row <rows;row++){ for(int col = 0; col < cols;col++){ int liveNeighbors = 0; for(int i =0; i <3;i++){ for(int j = 0; j < 3;j++){ if(!(neighbors[i] == 0 && neighbors[j] == 0)){ int r = (row +neighbors[i]); int c = (col + neighbors[j]); if ((r <rows && r>=0)&&(c < cols && c>= 0)&&(copyBoard[r][c] == 1)){ liveNeighbors += 1; } } } } if((copyBoard[row][col] == 1)&&(liveNeighbors <2 || liveNeighbors >3)){ board[row][col] = 0; } if (copyBoard[row][col] == 0&& liveNeighbors == 3){ board[row][col] = 1; } } } } }
方法二:O(mn)O(1)
class Solution { public void gameOfLife(int[][] board) { int [] neighbors = {0,1,-1}; int rows = board.length; int cols = board[0].length; for(int row = 0; row <rows;row++){ for(int col = 0; col < cols;col++){ int liveNeighbors = 0; for(int i =0; i <3;i++){ for(int j = 0; j < 3;j++){ if(!(neighbors[i] == 0 && neighbors[j] == 0)){ int r = (row +neighbors[i]); int c = (col + neighbors[j]); if ((r <rows && r>=0)&&(c < cols && c>= 0)&&(Math.abs(board[r][c]) == 1)){ liveNeighbors += 1; } } } } if((board[row][col] == 1)&&(liveNeighbors <2 || liveNeighbors >3)){ board[row][col] = -1; } if (board[row][col] == 0&& liveNeighbors == 3){ board[row][col] = 2; } } } for(int row = 0;row<rows;row++){ for(int col = 0;col< cols; col++){ if (board[row][col] > 0){ board[row][col] = 1; }else{ board[row][col] = 0; } } } } }
标签:游戏,int,col,289,board,&&,leetcode,liveNeighbors,row 来源: https://www.cnblogs.com/oldby/p/12620843.html