CodeGo.net>如何解析Json.NET多态对象？

我编写了一个Web服务,该服务发送和返回使用Json.NET创建的json.我已经包含了允许多态的类型名.有了bit of hacking,我已经可以在Silverlight客户端上使用它,但是我不知道如何使它适用于javascript客户端.

如何使用javascript解析？

{
  "$type": "MyAssembly.Zoo, MyAssembly",
  "ID": 1,
  "Animals": [
    {
      "$type": "MyAssembly.Dog, MyAssembly",
      "LikesBones": true,
      "Name": "Fido"
    },
    {
      "$type": "MyAssembly.Cat, MyAssembly",
      "LikesMice": false,
      "Name": "Felix"
    }
  ]
}

这是c#类：

public class Animal
{
    public string Name { get; set; }
}
public class Dog : Animal
{
    public bool LikesBones { get; set; }
}
public class Cat : Animal
{
    public bool LikesMice { get; set; }
}
public class Zoo
{
    public int ID { get; set; }
    private List<Animal> m_Animals = new List<Animal>();
    public List<Animal> Animals { get { return m_Animals; } set { m_Animals = value; } }
    public static void Test1()
    {
        Zoo z1 = new Zoo() { ID = 1 };
        z1.Animals.Add(new Dog() { Name = "Fido", LikesBones = true });
        z1.Animals.Add(new Cat() { Name = "Felix", LikesMice = false });
        var settings = new JsonSerializerSettings();
        settings.TypeNameHandling = TypeNameHandling.Objects;

        string s1 = JsonConvert.SerializeObject(z1, Formatting.Indented, settings);
        Debug.WriteLine(s1);

        var z2 = JsonConvert.DeserializeObject<Zoo>(s1, settings);
        foreach (Animal a in z2.Animals)
        {
            if (a is Dog)
                Debug.WriteLine(((Dog)a).LikesBones);
            else if (a is Cat)
                Debug.WriteLine (((Cat)a).LikesMice);
            else
                Debug.WriteLine("error");
        }

    }
}

解决方法:

要进行实际的解析,可以使用json2.js或JQuery的$.parseJSON()方法.这些将创建一个JavaScript对象,该对象与您发送的JSON直接相似.

由于Javascript是一种脚本语言,因此您不再需要考虑“多态性”,但是您应该能够像这样评估对象的属性(无需关心对象的“类型”)：

var obj = $.parseJSON(json);
var firstAnimalName = obj.Animals[0].Name;

标签：json-net,json,javascript,c
来源： https://codeday.me/bug/20191208/2091370.html