使用bs4提取html文件中的文本
作者:互联网
要从我的html文件中提取文本.如果我在下面使用特定文件:
import bs4, sys
from urllib import urlopen
#filin = open(sys.argv[1], 'r')
filin = '/home/iykeln/Desktop/R_work/file1.html'
webpage = urlopen(filin).read().decode('utf-8')
soup = bs4.BeautifulSoup(webpage)
for node in soup.findAll('html'):
print u''.join(node.findAll(text=True)).encode('utf-8')
它会工作.
但是下面尝试使用open(sys.argv [1],’r’)来查找非特定文件:
import bs4, sys
from urllib import urlopen
filin = open(sys.argv[1], 'r')
#filin = '/home/iykeln/Desktop/R_work/file1.html'
webpage = urlopen(filin).read().decode('utf-8')
soup = bs4.BeautifulSoup(webpage)
for node in soup.findAll('html'):
print u''.join(node.findAll(text=True)).encode('utf-8')
要么
import bs4, sys
from urllib import urlopen
with open(sys.argv[1], 'r') as filin:
webpage = urlopen(filin).read().decode('utf-8')
soup = bs4.BeautifulSoup(webpage)
for node in soup.findAll('html'):
print u''.join(node.findAll(text=True)).encode('utf-8')
我将在下面收到错误消息:
Traceback (most recent call last):
File "/home/iykeln/Desktop/py/clean.py", line 5, in <module>
webpage = urlopen(filin).read().decode('utf-8')
File "/usr/lib/python2.7/urllib.py", line 87, in urlopen
return opener.open(url)
File "/usr/lib/python2.7/urllib.py", line 180, in open
fullurl = unwrap(toBytes(fullurl))
File "/usr/lib/python2.7/urllib.py", line 1057, in unwrap
url = url.strip()
AttributeError: 'file' object has no attribute 'strip'
解决方法:
您不应该调用open,只需将文件名传递给urlopen:
import bs4, sys
from urllib import urlopen
webpage = urlopen(sys.argv[1]).read().decode('utf-8')
soup = bs4.BeautifulSoup(webpage)
for node in soup.findAll('html'):
print u''.join(node.findAll(text=True)).encode('utf-8')
仅供参考,您不需要urllib即可打开本地文件:
import bs4, sys
with open(sys.argv[1], 'r') as f:
webpage = f.read().decode('utf-8')
soup = bs4.BeautifulSoup(webpage)
for node in soup.findAll('html'):
print u''.join(node.findAll(text=True)).encode('utf-8')
希望能有所帮助.
标签:python-2-7,beautifulsoup,html-parsing,python 来源: https://codeday.me/bug/20191122/2063777.html