阿里钉钉面试题

定义一个类对list进行封装,使得可以用下标对list进行操作:
 1 #include <list>
 2 #include <vector>
 3 #include <iostream>
 4 #include <string> 
 5 
 6 using namespace std;
 7 
 8 class Test
 9 {
10 public:
11     Test();
12     //~Test();
13     Test(list<string> strList);
14     string &operator[](int n); //一般这里需要有&的,可以防止对象返回时去调用构造函数(因为return值,会有一个把值拷贝下来的过程)
15 
16 public:
17     list<string> m_strList;
18 };
19 
20 
21 Test::Test(list<string> strList)
22 {
23     m_strList = strList;
24 }
25 
26 //Test::~Test()    //当定义析构函数,而没有实现时会报错.
27 //{
28 //
29 //}
30 
31 string& Test::operator[](int n)
32 {
33     list<string>::iterator i = m_strList.begin();
34     vector<list<string>::iterator> vecStrIter;
35     for (; i != m_strList.end(); i++)
36     {
37         vecStrIter.push_back(i);
38     }
39     return *(vecStrIter[n]);
40 }
41 
42 
43 int main()
44 {
45     string str[4] = {"a", "li", "ba", "ba!"};
46     list<string> strList(str, str+4);
47     Test test(strList);
48     cout << test[1] << endl;
49     return 0;
50 }

标签：面试题,string,list,阿里,str,Test,strList,include
来源： https://www.cnblogs.com/Stephen-Qin/p/11846021.html