Android服务执行被拒绝

我有一个实现为WakefulIntentService的服务.每次启动适当的意图给负责的BroadcastReceiver时,就会启动该服务.该服务在两种情况下启动：在设备启动时以及该服务的运行实例即将完成时,并通过要求Android的常规任务计划程序AlarmManager在将来的时间发出启动程序意图来计划新的执行.

问题是,出于安全原因,我have been advised不要在清单文件中声明的服务中使用android：exported =“ true”.但是,如果忽略它,则会导致其中一部测试手机(运行Android 4.1.2的Samsung S3)拒绝执行服务：

06-13 11:34:34.181: W/ActivityManager(2270): Permission denied: checkComponentPermission() owningUid=10155
06-13 11:34:34.181: W/ActivityManager(2270): Permission Denial: Accessing service ComponentInfo{com.mypackage.myapp/com.mypackage.myapp.MyService} from pid=10320, uid=2000 that is not exported from uid 10155

添加android：exported =“ true”可解决此问题.是否有其他选择可以避免执行被拒绝而不损害应用程序的安全性？

清单xml文件：

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.mypackage.myapp"
    android:versionCode="3"
    android:versionName="1.0">

    <uses-sdk
        android:minSdkVersion="8"
        android:targetSdkVersion="17" />

    <uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
    <uses-permission android:name="android.permission.INTERNET" />
    <uses-permission android:name="android.permission.READ_PHONE_STATE" />
    <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
    <uses-permission android:name="android.permission.WAKE_LOCK" />

    <application
        android:allowBackup="true"
        android:icon="@drawable/ic"
        android:label="@string/app_name"
        android:theme="@style/AppTheme" >

        <receiver android:name=".MyBroadcastReceiver" >
            <intent-filter>
                <action android:name="android.intent.action.BOOT_COMPLETED" />
                <category android:name="android.intent.category.DEFAULT" />
            </intent-filter>
            <intent-filter>
                <action android:name="com.mypackage.myapp" />
            </intent-filter>
        </receiver>

        <service
            android:name="com.mypackage.myapp.MyService"
            android:exported="true">
        </service>

    </application>

</manifest>

BroadcastReceiver：

package com.mypackage.myapp;

import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;

import com.commonsware.cwac.wakeful.WakefulIntentService;

public class MyBroadcastReceiver extends BroadcastReceiver {

    @Override
    public void onReceive(Context context, Intent intent) {
        WakefulIntentService.sendWakefulWork(context, MyService.class);
    }
}

该服务在onDestroy()中包含启动程序意图调度代码：

public class MyService extends WakefulIntentService {

(...)

    @Override
    public void doWakefulWork(Intent intent) {
        (...)
    }

    @Override
    public void onDestroy() {

        PendingIntent pi = PendingIntent.getBroadcast(this, 0, new Intent("com.mypackage.myapp"), 0);

        AlarmManager am = (AlarmManager)(this.getSystemService(Context.ALARM_SERVICE));

        am.set(AlarmManager.ELAPSED_REALTIME_WAKEUP, ONE_MINUTE, pi);

        super.onDestroy();
    }
}

解决方法:

Actually it doesn’t occur from boot but when I attempt to start it manually on adb shell: am startservice com.mypackage.myapp/.MyService.

那不要那样做您的用户不会这样做.导出服务只是为了您可以运行adb shell命令,这并不是一个特别明智的举动.此外,您可以测试从adb shell发送启动时广播,达到相同的目的,而不必导出服务.

I haven’t been able to make the service start upon boot after removing the action string in my new Intent()

抱歉,我的意思是您的第二个动作字符串.您的<接收者>应该看起来像：

    <receiver android:name=".MyBroadcastReceiver" >
        <intent-filter>
            <action android:name="android.intent.action.BOOT_COMPLETED" />
            <category android:name="android.intent.category.DEFAULT" />
        </intent-filter>
    </receiver>

相应的PendingIntent将是：

PendingIntent pi = PendingIntent.getBroadcast(this, 0, new Intent(this, MyBroadcastReceiver.class), 0);

标签：android-intent,android-alarms,commonsware-cwac,android
来源： https://codeday.me/bug/20191030/1970518.html