POJ - 3259 - Wormholes = SPFA
作者:互联网
http://poj.org/problem?id=3259
看见500的数据量莽了一发Floyd,还T了。讲道理应该不至于的,换个快读试试。
#include<algorithm>
#include<cmath>
#include<cstdio>
#include<cstring>
#include<iostream>
#include<map>
#include<set>
#include<stack>
#include<string>
#include<queue>
#include<vector>
using namespace std;
typedef long long ll;
const int MAXN = 500;
int dis[MAXN + 5][MAXN + 5];
int main() {
#ifdef Yinku
freopen("Yinku.in", "r", stdin);
#endif // Yinku
int t;
scanf("%d", &t);
while(t--) {
memset(dis, 0x3f, sizeof(dis));
int n, m, l;
scanf("%d%d%d", &n, &m, &l);
for(int i = 1; i <= n; ++i) {
dis[i][i] = 0;
}
for(int i = 1; i <= m; ++i) {
int u, v, w;
scanf("%d%d%d", &u, &v, &w);
dis[u][v] = min(dis[u][v], w);
dis[v][u] = min(dis[v][u], w);
}
for(int i = 1; i <= l; ++i) {
int u, v, w;
scanf("%d%d%d", &u, &v, &w);
dis[u][v] = min(dis[u][v], -w);
}
bool suc = 0;
for(int k = 1; k <= n; ++k) {
for(int i = 1; i <= n; ++i) {
for(int j = 1; j <= n; ++j) {
dis[i][j] = min(dis[i][j], dis[i][k] + dis[k][j]);
}
if(dis[i][i] < 0) {
suc = 1;
break;
}
}
if(suc)
break;
}
puts(suc ? "YES" : "NO");
}
}
但是假如图本身连通的话,写SPFA就可以了。
#include<algorithm>
#include<cmath>
#include<cstdio>
#include<cstring>
#include<iostream>
#include<map>
#include<set>
#include<stack>
#include<string>
#include<queue>
#include<vector>
using namespace std;
typedef long long ll;
const int MAXN = 505;
const int MAXM = 10005;
int top;
int head[MAXN];
struct Edge {
int v, nxt;
int w;
} edge[MAXM];
void init() {
top = 0;
memset(head, -1, sizeof(head));
}
void add_edge(int u, int v, int w) {
++top;
edge[top].v = v;
edge[top].w = w;
edge[top].nxt = head[u];
head[u] = top;
}
bool vis[MAXN];
int cnt[MAXN];
int dis[MAXN];
queue<int>q;
bool spfa(int s, int n) {
memset(vis, 0, sizeof(vis));
memset(cnt, 0, sizeof(cnt));
for(int i = 0; i < MAXN; ++i)
dis[i] = 0x3f3f3f3f;
while(!q.empty())
q.pop();
q.push(s);
vis[s] = 1;
cnt[s] = 1;
dis[s] = 0;
while(!q.empty()) {
int u = q.front();
q.pop();
vis[u] = 0;
for(int i = head[u]; i != -1; i = edge[i].nxt) {
int v = edge[i].v;
if(dis[v] > dis[u] + edge[i].w) {
dis[v] = dis[u] + edge[i].w;
if(!vis[v]) {
vis[v] = 1;
q.push(v);
if(++cnt[v] > n)
return 0;
}
}
}
}
return 1;
}
int main() {
#ifdef Yinku
freopen("Yinku.in", "r", stdin);
#endif // Yinku
int t;
scanf("%d", &t);
while(t--) {
int n, m, l;
scanf("%d%d%d", &n, &m, &l);
init();
for(int i = 1; i <= m; ++i) {
int u, v, w;
scanf("%d%d%d", &u, &v, &w);
add_edge(u, v, w);
add_edge(v, u, w);
}
for(int i = 1; i <= l; ++i) {
int u, v, w;
scanf("%d%d%d", &u, &v, &w);
add_edge(u, v, -w);
}
bool suc = !spfa(1, n);
puts(suc ? "YES" : "NO");
}
}
速度172ms,可能可以试试优化。
标签:3259,int,top,SPFA,edge,POJ,MAXN,include,dis 来源: https://www.cnblogs.com/Inko/p/11728777.html