Week2 #4 Tomorrow never knows？
作者：互联网
编程题＃4：Tomorrow never knows？
来源: POJ (Coursera声明：在POJ上完成的习题将不会计入Coursera的最后成绩。)
注意： 总时间限制: 1000ms 内存限制: 65536kB
描述
甲壳虫的《A day in the life》和《Tomorrow never knows》脍炙人口，如果告诉你a day in the life,真的会是tomorrow never knows?相信学了计概之后这个不会是难题，现在就来实现吧。
读入一个格式为yyyy-mm-dd的日期（即年－月－日），输出这个日期下一天的日期。可以假定输入的日期不早于1600-01-01，也不晚于2999-12-30。
输入
输入仅一行，格式为yyyy-mm-dd的日期。
输出
输出也仅一行，格式为yyyy-mm-dd的日期
样例输入
2010-07-05样例输出
2010-07-06提示
闰年的标准：
(1)普通年能被4整除且不能被100整除的为闰年。（如2004年就是闰年,1901年不是闰年）
(2)世纪年能被400整除的是闰年。(如2000年是闰年，1100年不是闰年)
可以利用一个字符变量吃掉输入的短横线（减号），输出时请活用setfill和setw 控制符。
#include<iostream>
#include<iomanip>
using namespace std;
int main() {
int year;
int month;
int day;
char str1;
char str2;
cin >> year >> str1 >> month >> str2 >> day;
int next_month=0;
int next_year=0;
int next_day=0;
int flag=0;//是否是闰年的标志
if (((year % 100 == 0) && (year % 400 == 0)) || ((year % 100 != 0) && (year % 4 == 0)))
flag = 1;
if (month == 1)
{
if (day < 31)
{
next_day = day + 1;
next_year = year;
next_month = next_month;
}
else
{
next_month = month + 1;
next_day = 1;
next_year = year;
}
}
if (month == 2)
{
if (flag == 1)
{
if (day < 29)
{
next_day = day + 1;
next_year = year;
next_month = month;
}
else
{
next_month = month + 1;
next_day = 1;
next_year = year;
}
}
else
{
if (flag == 0)
{
if (day < 28)
{
next_day = day + 1;
next_month = month;
next_year = year;
}
else
{
next_month = month + 1;
next_day = 1;
next_year = year;
}
}
}
}
if (month == 3)
{
if (day < 31)
{
next_day = day + 1;
next_month = month;
next_year = year;
}
else
{
next_month = month + 1;
next_day = 1;
next_year = year;
}
}
if (month == 4)
{
if (day < 30)
{
next_year = year;
next_month = month;
next_day = day + 1;
}
else
{
next_month = month + 1;
next_day = 1;
next_year = year;
}
}
if (month == 5)
{
if (day < 31)
{
next_month = month;
next_year = year;
next_day = day + 1;
}
else
{
next_year = year;
next_month = month + 1;
next_day = 1;
}
}
if (month == 6)
{
if (day < 30)
{
next_year = year;
next_month = month;
next_day = day + 1;
}
else
{
next_year = year;
next_month = month + 1;
next_day = 1;
}
}
if (month == 7)
{
if (day < 31)
{
next_year = year;
next_month = month;
next_day = day + 1;
}
else
{
next_month=month+1;
next_day = 1;
next_year = year;
}
}
if (month == 8)
{
if (day < 31)
{
next_day = day + 1;
next_month = month;
next_year = year;
}
else
{
next_year = year;
next_month=month+1;
next_day = 1;
}
}
if (month == 9)
{
if (day < 30)
{
next_day = day + 1;
next_year = year;
next_month = year;
}
else
{
next_month=month+1;
next_day = 1;
next_year = year;
}
}
if (month == 10)
{
if (day < 31)
{
next_day = day + 1;
next_year = year;
next_month = month;
}
else
{
next_month=month+1;
next_day = 1;
next_year = year;
}
}
if (month == 11)
{
if (day < 30)
{
next_day = day + 1;
next_month = month;
next_year = year;
}
else
{
next_month=month+1;
next_day = 1;
next_year = year;
}
}
if (month == 12)
{
if (day < 31)
{
next_day=day+1;
next_month = month;
next_year = year;
}
else
{
next_year=year+1;
next_month = 1;
next_day = 1;
}
}
cout << next_year << str1 << setw(2) << setfill('0') << next_month << str2 << setw(2) << setfill('0') << next_day << endl;
return 0;
}
代码写的又臭又长；中间错了好几次，改了好几次，这样写工作量太大，出错也难排错；考虑将每月的天数做成一个对应天数的数组，可能会简化一点，也许只需要做一次对月份的if判断就可以，具体还没有操作过。
标签：int,never,month,next,else,year,Week2,Tomorrow,day 来源： https://www.cnblogs.com/xyhzq99/p/11644306.html