尽管一切似乎都已到位,但ifstream文件仍无法打开(c)

我正在尝试编写一个程序来解析CSV文件的第一列和第十六列(转换为.txt).我在包含可执行文件的文件夹中有CSV(“posts.txt”)文档.但是,每当我尝试运行可执行文件时,我的程序都会传递它无法打开文件(或“！infile.is_open()”).介意给我一些帮助？我在Mac OSX 10.8.3上运行Xcode 3.2.3.代码如下所示.

#include <iostream>
#include <fstream>
#include <cstdlib>
#include <string.h>

using namespace std;

void answeredPostGrabber()
{
    ifstream inFile("posts.txt");

    string postNumber;
    string answerNumber;
    string throwAway;

    if(inFile.is_open())
    {

        while(inFile.good())
        {
            getline(inFile,postNumber,',');
            cout << postNumber << ",";

            for(int y=1;y++;y<16)
            {
                getline(inFile,throwAway,',');
            }
            getline(inFile,answerNumber,',');
            cout << answerNumber << endl;

            ofstream edges;
            edges.open("edges.txt",ios::app);
            edges << postNumber << "," << answerNumber<< endl;
            edges.close();

            ofstream nodes;
            nodes.open("nodes.txt",ios::app);
            nodes << postNumber << "\n" << answerNumber << endl;
            nodes.close();

            getline(inFile,throwAway);
          }
   }else cout << "ERROR: Unable to open file." << endl;
}

int main ()
{
    answeredPostGrabber();
    return 0;
}

先感谢您！

解决方法:

I have the CSV (“posts.txt”) document in the folder with the executable.

该文件应存在于进程的current working directory中,该进程可能与可执行文件所在的目录相同,也可能不同.如果有疑问,请尝试在ifstream inFile(…)中指定完整路径;看看是否会改变一切.

此外,该文件需要具有正确的权限,以确保该进程可读取.

标签：ifstream,c,file
来源： https://codeday.me/bug/20191007/1866655.html