如何用pyaudio播放audiofile？

我不理解pyaudio的示例材料.看来他们已经编写了一个完整的小程序,它让我失望了.

我如何只播放一个音频文件？

格式不是问题,我只想知道播放音频文件所需的最小代码.

解决方法:

这个例子对我来说非常清楚.您只需将示例保存为playwav.py调用：

python playwav.py my_fav_wav.wav

波浪示例带有一些额外的评论：

import pyaudio
import wave
import sys

# length of data to read.
chunk = 1024

# validation. If a wave file hasn't been specified, exit.
if len(sys.argv) < 2:
    print "Plays a wave file.\n\n" +\
          "Usage: %s filename.wav" % sys.argv[0]
    sys.exit(-1)

'''
************************************************************************
      This is the start of the "minimum needed to read a wave"
************************************************************************
'''
# open the file for reading.
wf = wave.open(sys.argv[1], 'rb')

# create an audio object
p = pyaudio.PyAudio()

# open stream based on the wave object which has been input.
stream = p.open(format =
                p.get_format_from_width(wf.getsampwidth()),
                channels = wf.getnchannels(),
                rate = wf.getframerate(),
                output = True)

# read data (based on the chunk size)
data = wf.readframes(chunk)

# play stream (looping from beginning of file to the end)
while data != '':
    # writing to the stream is what *actually* plays the sound.
    stream.write(data)
    data = wf.readframes(chunk)

# cleanup stuff.
stream.close()    
p.terminate()

标签：python,audio,pyaudio
来源： https://codeday.me/bug/20191006/1858348.html