c – glEvalCoord与glFeedback一起使用时没有按预期提供输出
作者:互联网
我试图从glEvalCoord读取值,但没有得到我应该得到的确切值.我的代码是
GLfloat ctrlpoints[4][3] = {
{ -4.0, -4.0, 0.0}, { -2.0, 4.0, 0.0},
{ 2.0, -4.0, 0.0}, { 4.0, 4.0, 0.0}};
void display()
{
glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT );
glEnable(GL_LIGHTING);
glMap1f(GL_MAP1_VERTEX_3, 0.0, 1.0, 3, 4, &ctrlpoints[0][0]);
glEnable(GL_MAP1_VERTEX_3);
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
GLint size;
GLfloat feedBuffer[1024];
glFeedbackBuffer (1024, GL_3D, feedBuffer);
glRenderMode (GL_FEEDBACK);
glBegin (GL_POINTS);
for (int i=0; i<=30; ++i)
{
GLfloat t = GLfloat(i)/30;
glEvalCoord1f(t);
}
glEnd();
size = glRenderMode (GL_RENDER);
cerr<<size<<endl;
}
现在,我不确定但不应该为曲线的x,y和z坐标给出30 * 3的值?但我只得到7 * 3的价值.而输出的大小是28.
解决方法:
我认为你的尺寸是28,因为你的投影/模型视图对剪掉了一些点.
尝试这个:
#include <GL/glut.h>
#include <iostream>
using namespace std;
void display()
{
glClear( GL_COLOR_BUFFER_BIT );
glMatrixMode( GL_PROJECTION );
glLoadIdentity();
double w = glutGet( GLUT_WINDOW_WIDTH );
double h = glutGet( GLUT_WINDOW_HEIGHT );
double ar = w / h;
glOrtho( -5 * ar, 5 * ar, -5, 5, -1, 1 );
glMatrixMode( GL_MODELVIEW );
glLoadIdentity();
GLfloat ctrlpoints[4][3] =
{
{ -4.0, -4.0, 0.0 }, { -2.0, 4.0, 0.0 },
{ 2.0, -4.0, 0.0 }, { 4.0, 4.0, 0.0 }
};
glMap1f(GL_MAP1_VERTEX_3, 0.0, 1.0, 3, 4, &ctrlpoints[0][0]);
glEnable(GL_MAP1_VERTEX_3);
GLfloat feedBuffer[1024];
glFeedbackBuffer (1024, GL_3D, feedBuffer);
glRenderMode (GL_FEEDBACK);
glPointSize( 5 );
glColor3ub( 255, 255, 255 );
glBegin (GL_POINTS);
for (int i=0; i<=30; ++i)
{
GLfloat t = GLfloat(i)/30;
glEvalCoord1f(t);
}
glEnd();
GLint size = glRenderMode (GL_RENDER);
cerr << size << endl;
glutSwapBuffers();
}
int main( int argc, char **argv )
{
glutInit( &argc, argv );
glutInitDisplayMode( GLUT_RGBA | GLUT_DOUBLE );
glutInitWindowSize( 640, 480 );
glutCreateWindow( "GLUT" );
glutDisplayFunc( display );
glutMainLoop();
return 0;
}
我添加了一个略大的投影矩阵.
有了这个我得到124的大小:
> 31分*每点3个浮点数= 93
> 31分* 1每点GL_POINT_TOKEN = 31
31 91 = 124
标签:c,opengl,evaluator 来源: https://codeday.me/bug/20191002/1842841.html